我以为我会对此感到高兴。
测试表
CREATE TABLE `opening_hours` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`eateries_id` int(11) DEFAULT NULL,
`day_of_week` int(11) DEFAULT NULL,
`start_time` time DEFAULT NULL,
`end_time` time DEFAULT NULL,
PRIMARY KEY (`id`)
)
测试数据
INSERT INTO `test`.`opening_hours`
(
`eateries_id`,
`day_of_week`,
`start_time`,
`end_time`)
SELECT 2 AS eateries_id, 1 AS day_of_week, '13:00' AS start_time, '15:00' as end_time union all
SELECT 2 AS eateries_id, 1 AS day_of_week, '17:00' AS start_time, '20:00' as end_time union all
SELECT 2 AS eateries_id, 2 AS day_of_week, '13:00' AS start_time, '15:00' as end_time union all
SELECT 2 AS eateries_id, 2 AS day_of_week, '17:00' AS start_time, '20:00' as end_time union all
SELECT 2 AS eateries_id, 3 AS day_of_week, '13:00' AS start_time, '15:00' as end_time union all
SELECT 2 AS eateries_id, 4 AS day_of_week, '13:00' AS start_time, '20:00' as end_time union all
SELECT 2 AS eateries_id, 5 AS day_of_week, '13:00' AS start_time, '15:00' as end_time union all
SELECT 2 AS eateries_id, 6 AS day_of_week, '13:00' AS start_time, '20:00' as end_time union all
SELECT 2 AS eateries_id, 7 AS day_of_week, '13:00' AS start_time, '21:00' as end_time
union all
SELECT 3 AS eateries_id, 1 AS day_of_week, '13:00' AS start_time, '15:00' as end_time union all
SELECT 3 AS eateries_id, 2 AS day_of_week, '13:00' AS start_time, '15:00' as end_time union all
SELECT 3 AS eateries_id, 3 AS day_of_week, '13:00' AS start_time, '15:00' as end_time union all
SELECT 3 AS eateries_id, 4 AS day_of_week, '13:00' AS start_time, '20:00' as end_time union all
SELECT 3 AS eateries_id, 5 AS day_of_week, '13:00' AS start_time, '15:00' as end_time union all
SELECT 3 AS eateries_id, 6 AS day_of_week, '13:00' AS start_time, '20:00' as end_time union all
SELECT 3 AS eateries_id, 7 AS day_of_week, '13:00' AS start_time, '21:00' as end_time
查看定义以合并每天的营业时间
CREATE VIEW `test`.`groupedhours`
AS
select `test`.`opening_hours`.`eateries_id` AS `eateries_id`,
`test`.`opening_hours`.`day_of_week` AS `day_of_week`,
group_concat(concat(date_format(`test`.`opening_hours`.`start_time`,'%l'),' - ',date_format(`test`.`opening_hours`.`end_time`,'%l %p')) order by `test`.`opening_hours`.`start_time` ASC separator ', ') AS `OpeningHours`
from `test`.`opening_hours`
group by `test`.`opening_hours`.`eateries_id`,`test`.`opening_hours`.`day_of_week`
查询以查找具有相同开放时间的连续日子的“岛屿”（基于 Itzik Ben Gan 的一个）
SET @rownum = NULL;
SET @rownum2 = NULL;
SELECT S.eateries_id,
concat(CASE WHEN
S.day_of_week <> E.day_of_week
THEN
CONCAT(CASE S.day_of_week
WHEN 1 THEN 'Su'
WHEN 2 THEN 'Mo'
WHEN 3 THEN 'Tu'
WHEN 4 THEN 'We'
WHEN 5 THEN 'Th'
WHEN 6 THEN 'Fr'
WHEN 7 THEN 'Sa'
End, ' - ')
ELSE ''
END,
CASE E.day_of_week
WHEN 1 THEN 'Su'
WHEN 2 THEN 'Mo'
WHEN 3 THEN 'Tu'
WHEN 4 THEN 'We'
WHEN 5 THEN 'Th'
WHEN 6 THEN 'Fr'
WHEN 7 THEN 'Sa'
End, ' ', S.OpeningHours) AS `Range`
FROM (
SELECT
A.day_of_week,
@rownum := IFNULL(@rownum, 0) + 1 AS rownum,
A.eateries_id,
A.OpeningHours
FROM `test`.`groupedhours` as A
WHERE NOT EXISTS(SELECT * FROM `test`.`groupedhours` B
WHERE A.eateries_id = B.eateries_id
AND A.OpeningHours = B.OpeningHours
AND B.day_of_week = A.day_of_week -1)
ORDER BY eateries_id,day_of_week) AS S
JOIN (
SELECT
A.day_of_week,
@rownum2 := IFNULL(@rownum2, 0) + 1 AS rownum,
A.eateries_id,
A.OpeningHours
FROM `test`.`groupedhours` as A
WHERE NOT EXISTS(SELECT * FROM `test`.`groupedhours` B
WHERE A.eateries_id = B.eateries_id
AND A.OpeningHours = B.OpeningHours
AND B.day_of_week = A.day_of_week + 1)
ORDER BY eateries_id,day_of_week) AS E
ON S.eateries_id = E.eateries_id AND
S.OpeningHours = S.OpeningHours AND
S.rownum = E.rownum
结果
eateries_id Range
2 Su - Mo 1 - 3 PM, 5 - 8 PM
2 Tu 1 - 3 PM
2 We 1 - 8 PM
2 Th 1 - 3 PM
2 Fr 1 - 8 PM
2 Sa 1 - 9 PM
3 Su - Tu 1 - 3 PM
3 We 1 - 8 PM
3 Th 1 - 3 PM
3 Fr 1 - 8 PM
3 Sa 1 - 9 PM