如何计算两个 timeStamp （不同天数）之间的分钟差？答案

【问题标题】：How to calculate the difference in minutes between two timeStamp ( with different days)?如何计算两个 timeStamp （不同天数）之间的分钟差？
【发布时间】：2019-09-15 20:47:06
【问题描述】：

我正在尝试计算两个 java TimeStamps 之间的分钟差，当我写时：时间戳t1,t2;

t2.getTime()-t1.getTime(); 它只返回两次之间的差值，并且我一直需要差异（包括几天）

【问题讨论】：

这听起来不太可能 - 在这种情况下，t1.getTime() 和 t2.getTime() 的值是多少？
例如：02/24/2019 13:58:00 02/25/2019 12:58:00 相差 :1380 分钟
对，没错——1380 分钟是 23 小时，这就是这两个值之间的差异。你期望它是什么？
我没有得到你想要的东西，抱歉。你想要几分钟，你想要几天，你想要什么？请解释清楚。
考虑将ThreeTenABP 添加到您的Android 项目中，这样您就可以避免使用旧的、设计不良和令人困惑的Timestamp 类，例如使用ChronoUnit.MINUTES.between 或Duration 类。现代 API 更易于使用，我相信它可以更直接地提供您需要的功能。

标签： java android time timestamp

【解决方案1】：

试试这个

long difftime = t1.getTime() - t2.getTime();
long seconds = diff / 1000;
long minutes = seconds / 60;
long hours = minutes / 60;
long days = hours / 24;

【讨论】：

【解决方案2】：

2 个时间戳之间的差异以毫秒为单位。之后应用数学：

// get time difference in seconds
long milliseconds = timestamp2.getTime() - timestamp1.getTime();
int seconds = (int) milliseconds / 1000;

// calculate hours minutes and seconds
int hours = seconds / 3600;
int minutes = (seconds % 3600) / 60;
seconds = (seconds % 3600) % 60;

【讨论】：

【解决方案3】：

假设您的意思是 java.sql.Timestamp，下面的代码似乎可以正常工作：

import java.sql.Timestamp;

class Scratch {

    public static final long MINUTES_PER_HOUR = 60;
    public static final long SECONDS_PER_MINUTE = 60;
    public static final long HOURS_PER_DAY = 24;
    public static final long MILLIS_PER_SECOND = 1000L;

    public static void main(String[] args) {
        long oneDayPlusFiveMinutesInMillis = (MILLIS_PER_SECOND * SECONDS_PER_MINUTE) * ( 5 + MINUTES_PER_HOUR * HOURS_PER_DAY);
        Timestamp t0 = new Timestamp(System.currentTimeMillis());
        Timestamp t1 = new Timestamp(t0.getTime() + oneDayPlusFiveMinutesInMillis);
        long diff = (t1.getTime() - t0.getTime()) / (MILLIS_PER_SECOND * SECONDS_PER_MINUTE);
        System.out.println("t1 - t0 = " + diff + " minutes");
    }
}

t1 - t0 = 1445 minutes

【讨论】：

【解决方案4】：

    Timestamp t1 = new Timestamp(new Date("04/26/2019 20:32:49").getTime());
    Timestamp t2 = new Timestamp(new Date("04/27/2019 19:32:49").getTime());

    long diff = t2.getTime() - t1.getTime();

    long diffSeconds = diff / 1000 % 60;
    long diffMinutes = diff / (60 * 1000) % 60;
    long diffHours = diff / (60 * 60 * 1000) % 24;
    long diffDays = diff / (24 * 60 * 60 * 1000);
    long diffTotMinutes = diff / (60 * 1000);

    System.out.println("Days: " + diffDays + " \nTime: " + diffHours + ":" + diffMinutes + ":" + diffSeconds);
    System.out.println("Total Minutes: " + diffTotMinutes);

输出：

Days: 0 
Time: 23:0:0
Total Minutes: 1380

【讨论】：

如果 t2 == "04/27/2019 19:32:49"
Days: 0 Time: 23:0:0