如何以特定格式打印 time_t？

Question

ls 命令以这种格式打印时间：

Aug 23 06:07 

如何将来自stat() 的mtime() 的时间转换为这种格式的当地时间？

Answer 1

使用strftime（需要先将time_t转换为struct tm*）：

char buff[20];
struct tm * timeinfo;
timeinfo = localtime (&mtime);
strftime(buff, sizeof(buff), "%b %d %H:%M", timeinfo);

格式：

%b - The abbreviated month name according to the current locale.

%d - The day of the month as a decimal number (range 01 to 31).

%H - The hour as a decimal number using a 24-hour clock (range 00 to 23).

%M - The minute as a decimal number (range 00 to 59).

这里是完整的代码：

struct stat info; 
char buff[20]; 
struct tm * timeinfo;

stat(workingFile, &info); 

timeinfo = localtime (&(info.st_mtime)); 
strftime(buff, 20, "%b %d %H:%M", timeinfo); 
printf("%s",buff);