在 Python 中计算时间跨度

Question

我在 Windows 64 位上使用 Python v2.x

我想实时记录两个时刻并计算时间跨度。 代码如下：

current_time1 = datetime.datetime.now().time() # first moment

# ... some statement...some loops...take some time...

current_time2 = datetime.datetime.now().time() # second moment

time_span = current_time1 - current_time2

显然最后一行是不可执行的，因为 current_time 不是整数，所以我的问题是，如何将此语句转换为整数来进行数学运算？转换为秒是我的第一个想法......

Answer 1

从另一个中减去一个datetime.datetime.now() 会得到一个datetime.timedelta 实例。如果你在上面运行dir()，你可能会发现一些有用的功能。

>>> x = datetime.datetime.now()
# wait a second or two or use time.sleep()
>>> y = datetime.datetime.now()
>>> z = y - x
>>> type(z)
<type 'datetime.timedelta'>
>>> print(list(filter(lambda x: not x.startswith("_"), dir(z))))
['days', 'max', 'microseconds', 'min', 'resolution', 'seconds', 'total_seconds']
>>> print(z.total_seconds())
2.31

Answer 2

current_time1 = datetime.datetime.now()
time.sleep(50)
current_time2 = datetime.datetime.now()

print (current_time2 - current_time1)

或者

time1 = time.time()
time.sleep(50)
time2 = time.time()
print("%s seconds"%(time2-time1))

Answer 3

import time

current_time1 = time.clock()
do_something()
current_time2 = time.clock()
print "%.2gs" % (current_time2-current_time1)

编辑：

from datetime import datetime, date

datetime.combine(date.today(), current_time2) - datetime.combine(date.today(), current_time1)

Answer 4

在 python 3.x 中使用time.perf_counter

import time

t1_start = time.perf_counter()

do_something() # your code goes here

t1_stop = time.perf_counter()
print("Elapsed time:", t1_stop - t1_start) # print performance indicator