如何让它仅显示当前 DATE 但在所选时区内？

Question

function ctDT(){

var now = new Date(); 
var today = new Date(now.getUTCFullYear(), now.getUTCMonth(), now.getUTCDate(),  now.getUTCHours(), now.getUTCMinutes(), now.getUTCSeconds());
var anHour = 1000 * 60 * 60;
today = new Date(today.getTime() - anHour * 5);

var hours = today.getHours();
var minutes = today.getMinutes();
var seconds = today.getSeconds();

if (hours >= 12){
meridiem = "";
}
else {
meridiem = "";
}


if (minutes<10){
minutes = "0" + minutes;
}
else {
minutes = minutes;
}

if (seconds<10){
seconds = "0" + seconds;
}
else {
seconds = seconds;
}

document.getElementById("ctDT").innerHTML = (hours + ":" + minutes + meridiem);

}

ctDT();

<div id="ctDT"></div>

我是 Javascript 新手，但我的朋友帮我做了一次展示。如何让它显示日期？

我可以看到有 getUTCDate，但是当我只用日期替换整个小时 + 分钟部分时，它就出错了。

Answer 1

使用这个 Date 对象方法：

var now = new Date();
now.toDateString();

document.getElementById("date").innerHTML = now;

<div id="date"></div>

Answer 2

使用您的代码，您仍然想做的就是获取日期、月份和年份。您可以使用getDate()、getMonth() 和getFullYear。

请记住将+1 添加到月份，因为JavaScript 月份从0 开始。

function ctDT(){

var now = new Date();

// Convert date to UTC
var nowUTC = new Date(now.getUTCFullYear(), now.getUTCMonth(), now.getUTCDate(),  now.getUTCHours(), now.getUTCMinutes(), now.getUTCSeconds());

// Add/Subtract offset from UTC
nowUTC.setHours(nowUTC.getHours()+1);

// Get date parts
var day = nowUTC.getDate();
var month = nowUTC.getMonth();
var year = nowUTC.getFullYear();

var hours = nowUTC.getHours();
var minutes = nowUTC.getMinutes();
var seconds = nowUTC.getSeconds();

if (hours >= 12){
meridiem = "";
}
else {
meridiem = "";
}


if (minutes<10){
minutes = "0" + minutes;
}
else {
minutes = minutes;
}

if (seconds<10){
seconds = "0" + seconds;
}
else {
seconds = seconds;
}

// Display
document.getElementById("ctDT").innerHTML = day + '/' + (month + 1) + '/' + year;
// document.getElementById("ctDT").innerHTML += ' ' + hours + ":" + minutes + meridiem;  //uncomment this line to display time as well

}

ctDT();

<div id="ctDT"></div>