3 罢工查询 SQL 2008

Question

我需要创建一个 SQL 查询，当某人在 3 个月内出现 3 次或更多时填充一个表。

我可以得到的数据是：

SELECT 'John Doe' AS Name, 1406 AS InstanceID, '2016-01-08 00:00:00.000' AS AbsenceStart, '2016-01-13 00:00:00.000' AS AbsenceEnd, 4 AS NoOfDays, 1 AS rnk
UNION ALL
SELECT 'John Doe' AS Name, 1493 AS InstanceID, '2016-02-02 00:00:00.000' AS AbsenceStart, '2016-02-05 00:00:00.000' AS AbsenceEnd, 4 AS NoOfDays, 2 AS rnk
UNION ALL
SELECT 'John Doe' AS Name, 1536 AS InstanceID, '2016-02-19 00:00:00.000' AS AbsenceStart, '2016-02-22 00:00:00.000' AS AbsenceEnd, 2 AS NoOfDays, 3 AS rnk
UNION ALL
SELECT 'John Doe' AS Name, 1547 AS InstanceID, '2016-02-26 00:00:00.000' AS AbsenceStart, '2016-03-10 00:00:00.000' AS AbsenceEnd, 10 AS NoOfDays, 4 AS rnk
UNION ALL
SELECT 'John Doe' AS Name, 1660 AS InstanceID, '2016-04-04 00:00:00.000' AS AbsenceStart, '2016-04-04 00:00:00.000' AS AbsenceEnd, 0.5 AS NoOfDays, 5 AS rnk
UNION ALL
SELECT 'John Doe' AS Name, 1666 AS InstanceID, '2016-04-07 00:00:00.000' AS AbsenceStart, '2016-04-14 00:00:00.000' AS AbsenceEnd, 6 AS NoOfDays, 6 AS rnk
UNION ALL
SELECT 'John Doe' AS Name, 1698 AS InstanceID, '2016-04-27 00:00:00.000' AS AbsenceStart, '2016-04-28 00:00:00.000' AS AbsenceEnd, 1 AS NoOfDays, 7 AS rnk

它给出了以下输出。

我需要设计一个查询，当 90 天内有超过 3 个实例时，该查询将进行标记。因此，对于上述日期 1406,1493,1536,1547,1660,1666 将全部标记（历史上）。理想情况下，查询将每天运行，并在记录第三个实例后立即设置警报。我尝试了各种 DATEDIFF 和派生查询，但似乎无法正常工作。 因此，所需的输出将是上表，但仅限于第一次缺勤开始 + 90 天的日期范围内的输出。我知道我错过了一些简单的东西！

Answer 1

您可以使用循环来执行此操作，请参阅下面的代码（已注释）。我将您的初始数据放入#temp：

if object_id('tempdb..#temp') is not null
drop table #temp

SELECT 'John Doe' AS Name, 1406 AS InstanceID, '2016-01-08 00:00:00.000' AS 

AbsenceStart, '2016-01-13 00:00:00.000' AS AbsenceEnd, 4 AS NoOfDays, 1 AS rnk
into #temp
UNION ALL
SELECT 'John Doe' AS Name, 1493 AS InstanceID, '2016-02-02 00:00:00.000' AS AbsenceStart, '2016-02-05 00:00:00.000' AS AbsenceEnd, 4 AS NoOfDays, 2 AS rnk
UNION ALL
SELECT 'John Doe' AS Name, 1536 AS InstanceID, '2016-02-19 00:00:00.000' AS AbsenceStart, '2016-02-22 00:00:00.000' AS AbsenceEnd, 2 AS NoOfDays, 3 AS rnk
UNION ALL
SELECT 'John Doe' AS Name, 1547 AS InstanceID, '2016-02-26 00:00:00.000' AS AbsenceStart, '2016-03-10 00:00:00.000' AS AbsenceEnd, 10 AS NoOfDays, 4 AS rnk
UNION ALL
SELECT 'John Doe' AS Name, 1660 AS InstanceID, '2016-04-04 00:00:00.000' AS AbsenceStart, '2016-04-04 00:00:00.000' AS AbsenceEnd, 0.5 AS NoOfDays, 5 AS rnk
UNION ALL
SELECT 'John Doe' AS Name, 1666 AS InstanceID, '2016-04-07 00:00:00.000' AS AbsenceStart, '2016-04-14 00:00:00.000' AS AbsenceEnd, 6 AS NoOfDays, 6 AS rnk
UNION ALL
SELECT 'John Doe' AS Name, 1698 AS InstanceID, '2016-04-27 00:00:00.000' AS AbsenceStart, '2016-04-28 00:00:00.000' AS AbsenceEnd, 1 AS NoOfDays, 7 AS rnk


-- First find the start rank:
declare @x int = (select top 1 rnk from #temp order by rnk asc)
-- Find the maximum number of records to loop through
declare @y int = (select top 1 rnk from #temp order by rnk desc)
-- This is your threshold for publishing
declare @a int

-- start loop
while @x <= @y


begin

if @a >=3
break; -- if threshold breached, stop loop.

else    

if object_id('tempdb..#list') is not null
drop table #list

declare @z datetime = (select AbsenceStart from #temp where rnk = @x)
print @z

select
instanceid,
AbsenceStart
into #list
from #temp
where AbsenceStart >= @z
and AbsenceStart <= dateadd(dd,90,@z)


set @a = (select count(instanceid) from #list)



set @x = @x + 1

print @x

end

insert into dbo.DestinationTable
select * 
from #list