【发布时间】:2016-08-01 18:41:09
【问题描述】:
我可以毫无问题地在画布上绘制图像。 但我希望在新窗口的画布上绘制图像。 变量具有正确的值,但仍然没有绘制任何内容。
这是我的代码:
var popup = window.open();
popup.oldCanvas= oldCanvas;
popup.url = 'http://www.html5canvastutorials.com/demos/assets/darth-vader.jpg';
popup.document.open();
popup.document.write("<html><head>");
popup.document.write('<script src="lib/jquery/jquery-2.1.1.min.js"></script>');
popup.document.write("<script>\n");
popup.document.write("$(document).ready(function() { \n");
popup.document.write(" function createCanvas() { \n");
popup.document.write(" var img = new Image;\n");
popup.document.write(" var newCanvas = document.createElement('canvas');\n");
popup.document.write(" var context = newCanvas.getContext('2d'); \n");
popup.document.write(" newCanvas.width = oldCanvas.width; \n");
popup.document.write(" newCanvas.height = oldCanvas.height; \n");
popup.document.write(" img.onload = function() {\n");
popup.document.write(" context.drawImage(this, 0, 0); \n");
popup.document.write(" }; \n");
popup.document.write(" img.src = url; \n");
popup.document.write(" }; \n");
popup.document.write(" createCanvas(); \n");
popup.document.write("}); \n");
popup.document.write("</script>");
popup.document.write("</head><body>");
popup.document.write("</body>");
popup.document.write("</html>");
popup.document.close();
请告诉我我做错了什么,因为相同的代码在没有在新窗口中绘制时可以正常工作。
【问题讨论】:
-
如果将
console.log(oldCanvas)放在$(document).ready下一行会怎样? -
打印 HTML 画布元素:
<canvas id="mycanvas" width="100" height="100"> -
在 document.write 版本中?你能把它放在一个jsfiddle吗?
-
这里是 plnkr:plnkr.co/edit/yZSTtAGdVVsSWmbfFJ0F
标签: javascript canvas html5-canvas drawimage