【发布时间】:2019-12-25 00:14:32
【问题描述】:
问题
我有一个搜索组件和实现搜索组件的组件。当我在 1/2 秒未输入(去抖动)后在搜索栏中输入内容时,应该会命中服务器并返回结果。
我尝试实施的解决方案来自this post on Stackoverflow
代码
这将我引向以下代码。
我有search.vue
<template>
<label for="search">
<input
id="search"
class="w-full py-2 px-1 border-gray-900 border"
type="text"
name=":searchTitle"
v-model="searchFilter"
:placeholder="searchPlaceholder"
autocomplete="off"
v-on:keydown="filteredDataset"
/>
</label>
</template>
<script>
import {debounce} from 'lodash';
export default {
props: {
searchPlaceholder: {
type: String,
required: false,
default: ''
},
searchName: {
type: String,
required: false,
default: 'search'
}
},
data() {
return {
searchFilter: '',
}
},
methods: {
filteredDataset() {
console.log('event fired');
this.$emit('searchValue', this.searchFilter);
}
},
}
</script>
还有product.vue
<template>
<div>
<div class="my-4">
<search
search-placeholder=""
search-name=""
v-on:searchValue="filterValue = $event"
v-model="productsFiltered"
>
</search>
<div class="flex w-full py-1 border px-2 my-2" v-for="product in productsFiltered"> (...)
</div>
</div>
</div>
</div>
</template>
<script>
import {debounce} from 'lodash';
export default {
data() {
return {
products: [],
filterValue: '',
filteredProducts: ''
}
},
computed: {
productsFiltered: {
get(){
console.log('getter called');
return this.filteredProducts;
},
set: _.debounce(function(){
console.log('setter called');
if (this.filterValue.length < 1) {
this.filteredProducts = [];
}
axios.get(`${apiUrl}search/` + this.filterValue)
.then(response => {
this.products = response.data.products;
const filtered = [];
const regOption = new RegExp(this.filterValue, 'ig');
for (const product of this.products) {
if (this.filterValue.length < 1 || product.productname.match(regOption)) {
filtered.push(product);
}
}
this.filteredProducts = filtered;
});
}, 500)
}
},
}
</script>
结果
结果是product.vue 中计算属性中的设置器没有被调用,并且没有从服务器获取数据。关于如何解决这个问题的任何想法?
【问题讨论】:
标签: ajax vue.js vuejs2 vue-component debouncing