如何在 Jenkins 中使用 groovy 脚本仅获取过去 24 小时的成功构建？

Question

我需要获取从当前脚本执行时间开始在过去 24 小时内成功运行的作业列表。 目前我只得到今天约会成功的工作，但我正在寻找最后 24 小时的工作，这可能是最后几天的工作，也可能在 24 小时内。

已经编写了一个脚本并获得了当前的结果，但不是 24 小时

import hudson.model.*
Date date = new Date()
String present = date.format("MM-dd-yyyy")
def str_view = "GitLab_jobs"
def view = Hudson.instance.getView(str_view)
def successfulJobs = view.getItems().findAll {
  job - > job.lastBuild != null && job.lastBuild.result == hudson.model.Result.SUCCESS && !job.name.contains("maintenance")
}
def faildJobs = view.getItems().findAll {
  job - > job.lastBuild != null && job.lastBuild.result == hudson.model.Result.FAILURE && !job.name.contains("maintenance")
}
def disabledJob = view.getItems().findAll {
  job - > job.disabled == true && !job.name.contains("maintenance")
}
def enabledJob = view.getItems().findAll {
  job - > job.disabled != true && !job.name.contains("maintenance")
}

println "Total jobs: " + view.getItems().size + " Successful: " + successfulJobs.size +
  " Failed: " + faildJobs.size + " Enabled jobs: " + enabledJob.size + " Disabled jobs: " + disabledJob.size



println "Current Successful job Today:"
successfulJobs.each {
  job - > printInfo(job)
}


def printInfo(job) {
  Date date = new Date()
  String datePart = date.format("MM-dd-yyyy")
  String timePart = date.format("HH:mm:ss")


  x = "${datePart}"

  y = "${job.lastBuild.getTime().format("
  MM - dd - yyyy ")}"

  if ("$x" == "$y") {
    println "Job: ${job.name} build on ${job.getAssignedLabelString()}, " +
      "Date ${job.lastBuild.getTime().format("
    MM - dd - yyyy ")}, is disabled : ${job.disabled}"
  }

}

实际结果应打印在过去 24 小时内成功完成的作业列表

Answer 1

试试

Date previousDayFromNow = new Date() - 1

if (previousDayFromNow < job.lastBuild.getTime()) {
    println "...job info..."
}