从对象数组返回最小值

Question

我有一个对象数组。在每个对象中都有一个包含多个对象的详细信息属性（数组）——在这个例子中我只展示了一个。

我正在寻找每个细节中的 rating 属性并寻找最小值（在本例中为 3.1）...是否有更简单/更清洁的方法来实现这一点？

const ratings = [{ id: 'ABC', details: [{ type: 'VALUE', rating: 9.5 }] }, { id: 'DEF', details: [{ type: 'VALUE', rating: 3.1 }] }, { id: 'GHI', details: [{ type: 'VALUE', rating: 4.5 }] }]
const ids = ['ABC', 'DEF', 'GHI']
const array = []

ids.forEach(element => {
  const valueScore = ratings?.find(r => r.id === element)?.details?.find(c => c.type === 'VALUE')
  if (valueScore.rating) {
    array.push(valueScore.rating)
  }
})
console.log('MIN VALUE', Math.min(...array))

Answer 1

你可以这样做：

为什么首选这种方法是，您可以在每个评级项以及每个详细信息数组项上完美地运行循环。

  ratings = [
    { id: "ABC", details: [{ type: "VALUE", rating: 9.5 }] },
    {
      id: "DEF",
      details: [{ type: "VALUE", rating: 3.1 }, { type: "VALUE1", rating: 2.1 }]
    },
    { id: "GHI", details: [{ type: "VALUE", rating: 4.5 }] }
  ];

  ids = ["ABC", "DEF", "GHI"];
    const detailsRatingArr = [];
    if (ratings.length === ids.length) {
      ratings.forEach(eachRating => {
        ids.forEach(eachId => {
          if (eachRating.id === eachId) {
            eachRating.details.forEach(eachDetail => {
              detailsRatingArr.push(eachDetail.rating);
            });
          }
        });
      });
    }
    console.log("DETAILS ARRAY ==>", detailsRatingArr);
    detailsRatingArr.sort((a, b) => a - b);
    console.log("Minimum Rating ==>", detailsRatingArr[0]);
  

Answer 2

您可以使用flatMap 然后应用 math.min 来获取最小值：

const ratings = [{ id: 'ABC', details: [{ type: 'VALUE', rating: 9.5 }] }, { id: 'DEF', details: [{ type: 'VALUE', rating: 3.1 },{ type: 'VALUE1', rating: 2.1 }] }, { id: 'GHI', details: [{ type: 'VALUE', rating: 4.5 }] }];

const ids = ['ABC', 'DEF', 'GHI']

console.log(Math.min(...ratings.flatMap(o=>
    ids.includes(o.id) ? o.details.flatMap(p=>
        p.type=='VALUE' ? p.rating : []) : [])));