如何将 Javascript 中的日志字符串解析为 JSON答案

【问题标题】：How to parse a log string in Javascript to a JSON如何将 Javascript 中的日志字符串解析为 JSON
【发布时间】：2021-04-13 04:29:43
【问题描述】：

我有一个如下所示的控制台字符串：

2021-01-06T09:06:05.541212726Z D saveGarment: Function execution took 736 ms, finished with status code: 204
2021-01-06T09:06:10.844901031Z D saveGarment: Function execution started
2021-01-06T09:06:16.153Z ? saveGarment: CORE
2021-01-06T09:06:18.134508823Z D saveGarment: Function execution took 7470 ms, finished with status code: 200
2021-01-06T09:06:19.546Z ? saveGarment: { message: 'fail' }

如何将此字符串解析为 JSON，使其看起来像这样：

{
  {
    date: '2021-01-06'
    time: '09:06:05'
    type: 'D'
    function: 'saveGarment'
    message: 'Function execution took 736 ms'
    statusCode: 204
  },
}

【问题讨论】：

你试过了吗？
您的控制台字符串会生成多少条记录？
@KevinZhang 不能说，它可以生成0甚至100
@Nicolas 我对正则表达式完全陌生，但我尝试使用正则表达式对不同的属性进行分组，但我仍然感到困惑
我的意思是，上面粘贴的当前控制台字符串。

标签： javascript json logging ecmascript-6 console

【解决方案1】：

使用Regex似乎有点难，我只是使用字符串操作来处理，代码如下：

let consoleLog = `2021-01-06T09:06:05.541212726Z D saveGarment: Function execution took 736 ms, finished with status code: 204
2021-01-06T09:06:10.844901031Z D saveGarment: Function execution started
2021-01-06T09:06:16.153Z ? saveGarment: CORE
2021-01-06T09:06:18.134508823Z D saveGarment: Function execution took 7470 ms, finished with status code: 200
2021-01-06T09:06:19.546Z ? saveGarment: { message: 'fail' }`;

let logs = consoleLog.split('\n');
let results: any = [];
console.clear();
logs.forEach(log => {
    let twoParts = splitFirstCh(log, ' ');
    let dateTime = twoParts[0];
    let twoParts1 = splitFirstCh(twoParts[1], ' ');
    let typeStr = twoParts1[0];
    let twoParts2 = splitFirstCh(twoParts1[1], ':');
    let message = '', statusCode = '';
    if (twoParts2[1].indexOf('status code') > -1) {
        message = splitLastCh(twoParts2[1], ',')[0];
        statusCode = splitLastCh(twoParts2[1], ':')[1].trim();
    } else if (twoParts2[1].indexOf('{') > -1) {
        message = splitLastCh(twoParts2[1], ':')[1].replace('}', '').trim();
        statusCode = '';
    } else {
        message = twoParts2[1].trim();
        statusCode = '';
    }

    let functionStr = twoParts2[0];
    results.push({
        date: new Date(dateTime).toLocaleDateString(),
        time: new Date(dateTime).toLocaleTimeString(),
        'type': typeStr,
        'function': functionStr,
        message: message,
        statusCode: statusCode
    });
});

console.log(results);

function splitFirstCh(data: string, ch: string) {
    return [data.substr(0, data.indexOf(ch)), data.substr(data.indexOf(ch) + 1)];
}

function splitLastCh(data: string, ch: string) {
    return [data.substr(0, data.lastIndexOf(ch)), data.substr(data.lastIndexOf(ch) + 1)];
}

【讨论】：