如何对对象进行排序以使所有值都按升序排列？

Question

我正在尝试做词频，并且我有一些工作可以打印出词频。我现在想按升序对输出进行排序。

var paragraph = "Into the bored patent composes the synonymous cheer. The playing essence mothers an offset. Does the alleged cap fast? Why can't the covered fish urge the word? The cyclist works within a laughing jam. When will my smooth year entitle the public?";

un_puncutated_paragraph = paragraph.replace(/[~`!@#$%^&*(){}\[\];:"'<,.>?\/\\|_+=-]/g,"");
let wordsHolder = un_puncutated_paragraph.split(' ');
let frequencyMap = {};

wordsHolder.forEach((word) => {
  if (!frequencyMap[word]) {
    frequencyMap[word] = 0;
  }
  frequencyMap[word] += 1;
});

另外，有人可以更好地解释这个逻辑，不完全确定发生了什么吗？

  if (!frequencyMap[word]) {
    frequencyMap[word] = 0;
  }
  frequencyMap[word] += 1;

谢谢！

Answer 1

要按照每个单词出现的频率对最终的frequencyMap 对象进行排序，您可以尝试：

Object.keys(frequencyMap)
    .sort()
    .reduce((a, v) => {
      a[v] = frequencyMap[v];
      return a; }, {});

Answer 2

 if (!frequencyMap[word]) { // If word does not exists as key in array...
    frequencyMap[word] = 0; // ...add key in array
  }
 frequencyMap[word] += 1; //  if existing or just created increment word count

Answer 3

var paragraph, arrText, getVal, finalString;
var objText = [],
  arrGetText = [];

paragraph = "Into the bored patent composes the synonymous cheer. The playing essence mothers an offset. Does the alleged cap fast? Why can't the covered fish urge the word? The cyclist works within a laughing jam. When will my smooth year entitle the public?";

// Step 1. Split Text with space
arrText = paragraph.split(" ");

// Step 2. Create length and text based object
for (var index = 0; index < arrText.length; index++) {
  objText.push({
    len: arrText[index].length,
    text: arrText[index]
  });
}

// Step 3. Sort object by length
objText.sort(function(a, b) {
  return a.len - b.len;
});

// Step 4. Extract value from sorted object and push into a new array
for (var index = 0; index < arrText.length; index++) {
  getVal = Object.values(objText[index]);
  arrGetText.push(getVal[1]);
}

// Step 5. Finally join array with with space and produce ascending order sorted string.
var finalString = arrGetText.join(" ");
console.log(finalString);