验证在 JavaScript 中设置为 JSON 的电子邮件扩展列表

Question

如何验证用户输入的电子邮件并使用 JSON 中的电子邮件扩展名列表检查他们的扩展名？

就像我输入 abc@efg.com 一样，它只会检查 JSON 列表中的电子邮件扩展名 @efg.com。

或者一个只会获取“@”之后的值并忽略之前的任何内容的正则表达式。

[
    {
        "School": "Ivy Tech Community College",
        "Email": "ivytech.edu"
    },
    {
        "School": "Liberty University",
        "Email": "liberty.edu"
    },
    {
        "School": "Miami Dade College",
        "Email": "mdc.edu"
    },
    {
        "School": "Lone Star College",
        "Email": "lonestar.edu"
    },
    {
        "School": "Ashford University",
        "Email": "ashford.edu"
    }
]

Answer 1

除了正则表达式，您可以遍历学校数组，并像这样匹配域：

var schools = [
    {"School":"Ivy Tech Community College","Email":"ivytech.edu"},
    {"School":"Liberty University","Email":"liberty.edu"},
    {"School":"Miami Dade College","Email":"mdc.edu"},
    {"School":"Lone Star College","Email":"lonestar.edu"},
    {"School":"Ashford University","Email":"ashford.edu"}
]

function validate(email) {
    var domain = email.split('@').pop();
    for(var i = 0; i < schools.length; i++) {
        if(domain === schools[i].Email) return schools[i].School;
    }

    return 'Domain Not Found';
}

您可以将schools[i].School 替换为true 并将'Domain Not Found' 替换为false 以检查它是否存在。

示例：https://jsfiddle.net/TheQueue841/gwhkq520/

Answer 2

提到的类似垃圾箱的东西会起作用：

var edus = [
    {"School":"Ivy Tech Community College","Email":"ivytech.edu"},
    {"School":"Liberty University","Email":"liberty.edu"},
    {"School":"Miami Dade College","Email":"mdc.edu"},
    {"School":"Lone Star College","Email":"lonestar.edu"},
    {"School":"Ashford University","Email":"ashford.edu"}
];

var emails = ['matty.fake@lonestar.edu','himom@mdc.edu','randomguy@yahoo.com'];

emails.forEach(function(element,index) {
  var domain = element.substring(element.indexOf('@') + 1);
  var match = 'none';
  if (domain) {
    edus.forEach(function(element,ind) {
      if (element.Email === domain) {
        match = element.School;
      }
    });
    console.log(element + ' matched ' + match);
  }
});

// matty.fake@lonestar.edu matched Lone Star College
// himom@mdc.edu matched Miami Dade College
// randomguy@yahoo.com matched none

Answer 3

// initial data
var data = '[ {"School":"Ivy Tech Community College","Email":"ivytech.edu"},' + '{"School":"Liberty University","Email":"liberty.edu"},' + '{"School":"Miami Dade College","Email":"mdc.edu"},' + '{"School":"Lone Star College","Email":"lonestar.edu"},' + '{"School":"Ashford University","Email":"ashford.edu"} ]';

// json-ify our data
var jsonData = JSON.parse(data);

// map the values of each JSON 'Email' property from jsonData in an array 
var emailsArray = jsonData.map(function (x) { return x.Email; });

// email address for testing
var testEmail = "john@liberty.edu";

// split the email address by the "@" character and use the second part (domain)
if (arrayContains(testEmail.split("@")[1], emailsArray))
{
    // this will fire as john@liberty.edu matches liberty.edu in emailsArray
    console.log("emailsArray contains domain");
}
else
{
    console.log("emailsArray does not contain domain");
}

// function to check if an item is contained in an array
function arrayContains(item, array)
{
    return (array.indexOf(item) > -1);
}

完整的 JSFiddle 示例here。

注意事项：

• 您可以忽略前两行代码，因为我猜您是从 Web 响应中获取 JSON 数据
• 假设testEmail 遵循电子邮件地址的格式；您可能需要实施某种验证来验证输入的字符串是实际的电子邮件
• 我们将testEmail 拆分为@ 字符并使用String.prototype.split() 获得结果的第二部分（将在索引1 处，因为数组是从零开始的）
• emailsArray 数组是使用 Array.prototype.map() 函数创建的
• arrayContains 使用String.prototype.indexOf() 方法检查testEmail 是否存在于emailsArray

我想我已经阐明了示例中每一行代码的作用。您现在可以使用它并根据自己的要求进行调整——甚至更好的是，改进它。

Answer 4

如果您只想验证，请使用Array.prototype.some()。

some() 对数组中存在的每个元素执行一次回调函数，直到找到一个回调函数返回一个真值（转换为布尔值时变为真值的值）。如果找到这样的元素， some() 立即返回 true。否则， some() 返回 false。回调仅针对已分配值的数组索引调用；它不会为已删除或从未被赋值的索引调用。

var schools = [
    {"School":"Ivy Tech Community College","Email":"ivytech.edu"},
    {"School":"Liberty University","Email":"liberty.edu"},
    {"School":"Miami Dade College","Email":"mdc.edu"},
    {"School":"Lone Star College","Email":"lonestar.edu"},
    {"School":"Ashford University","Email":"ashford.edu"}
]

function validate(email) {
    var domain = email.split('@').pop();
    return schools.some(function(school) {
    	return school.Email === domain;
    });
}

validate('test@ashford.edu');