【发布时间】:2016-01-07 14:04:16
【问题描述】:
我有某些网址,例如:
http://www.moneycontrol.com/news/business/vistaras-turbulent-takeoffthe-cut-throat-indian-skies_3510081.html
http://www.business-standard.com/article/markets/patanjali-ayurved-targets-250-revenue-growth-in-fy16-edelweiss-115100900788_1.html
这些可以是任何网站 URL。如何从内容中提取www.moneycontrol.com 或www.business-standard.com?
【问题讨论】:
-
看看gist.github.com/acdcjunior/9820040:
var myDomain = new ParsedUrl("http://www.moneycontrol.com/news/business/vistaras-turbulent-takeoffthe-cut-throat-indian-skies_3510081.html").host; -
这里是不使用拆分的版本:
var domains = urls.map(function(url) { var a = document.createElement("a"); a.href=url; return a.hostname; });
标签: javascript regex string