【发布时间】:2020-12-11 13:06:55
【问题描述】:
当在下拉菜单中选择一个选项时,即使按下它,它也不会在按钮上改变。我也尝试在 javascript 上进行控制台记录,但它不打印,而是在 chrome 检查器上显示以下错误:
index.js:26 Uncaught TypeError: Cannot read property 'value' of null
at getSelectValue (index.js:26)
at index.js:29
我的html是:
<!DOCTYPE html>
<html lang="en" dir="ltr">
<head>
<meta charset="utf-8">
<title>Titlee</title>
<!-- Favicon -->
<link rel="short icon" type="image" href="dicelogo.png">
<!-- Bootstrap, CSS -->
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.5.0/css/bootstrap.min.css" integrity="sha384-9aIt2nRpC12Uk9gS9baDl411NQApFmC26EwAOH8WgZl5MYYxFfc+NcPb1dKGj7Sk" crossorigin="anonymous">
<link rel="stylesheet" href="styles.css">
<!-- Google Font -->
<link href="https://fonts.googleapis.com/css2?family=PT+Mono&display=swap" rel="stylesheet">
<link href="https://fonts.googleapis.com/css?family=Indie+Flower|Lobster" rel="stylesheet">
<!-- Jquery Links -->
<script src="https://code.jquery.com/jquery-3.3.1.slim.min.js" integrity="sha384-q8i/X+965DzO0rT7abK41JStQIAqVgRVzpbzo5smXKp4YfRvH+8abtTE1Pi6jizo" crossorigin="anonymous"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.7/umd/popper.min.js" integrity="sha384-UO2eT0CpHqdSJQ6hJty5KVphtPhzWj9WO1clHTMGa3JDZwrnQq4sF86dIHNDz0W1" crossorigin="anonymous"></script>
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/js/bootstrap.min.js" integrity="sha384-JjSmVgyd0p3pXB1rRibZUAYoIIy6OrQ6VrjIEaFf/nJGzIxFDsf4x0xIM+B07jRM" crossorigin="anonymous"></script>
</head>
<body>
<div class="container-fluid user-interaction">
<h1>How to play?</h1>
<h5>Write down your choices here (you can choose up to 4):</h5>
<!-- Dropdown Button -->
<div class="dropdown">
<button class="btn btn-info dropdown-toggle" type="button" id="dropdownMenu1" data-toggle="dropdown" aria-haspopup="true" aria-expanded="true">
2
<span class="caret"></span>
</button>
<ul id="list" class="dropdown-menu dropdown-info" onchange="getSelectedValue();" aria-labelledby="dropdownMenu1">
<li><a href="#">2</a></li>
<li><a href="#">3</a></li>
<li><a href="#">4</a></li>
</ul>
</div>
<input type="text" name="" value="" placeholder="">
</div>
<script src="index.js" charset="utf-8">
</script>
</body>
<footer>
???? Thanks for playing ????
</footer>
</html>
我的 javascript 是:
// Default Dice
// 1st image
var randomNumber1 = Math.floor(Math.random() * 6 + 1);
var Image1 = "dice" + randomNumber1 + ".png";
document.querySelectorAll("img")[1].setAttribute("src", Image1);
// 2nd image
var randomNumber2 = Math.floor(Math.random() * 6 + 1);
var Image2 = "dice" + randomNumber2 + ".png";
document.querySelectorAll("img")[2].setAttribute("src", Image2);
// 3rd image
var randomNumber3 = Math.floor(Math.random() * 6 + 1);
var Image3 = "dice" + randomNumber3 + ".png";
document.querySelectorAll("img")[3].setAttribute("src", Image3);
// 4th image
var randomNumber3 = Math.floor(Math.random() * 6 + 1);
var Image4 = "dice" + randomNumber3 + ".png";
document.querySelectorAll("img")[4].setAttribute("src", Image4);
var diceNumbers = []
// selectedNumber
function getSelectValue() {
var selectedValue = document.getElementById("list").value;
console.log(selectedValue);
}
getSelectValue();
// Determining Winner
如何使选择的数字被选中并打印在控制台日志上?提前致谢
【问题讨论】:
-
var selectedValue = document.getElementById("list") 您没有具有此 ID 的项目
-
@Unbywyd 即使在我将 Id 添加到
- 之后,它也不起作用
标签: javascript html bootstrap-4