【发布时间】:2011-09-12 17:05:57
【问题描述】:
当我使用 IRB 创建新模型实例并保存时,控制台没有任何内容打印出来,并且我收到“ActiveRecord::StatementInvalid: Mysql::Error: Column 'user_id' cannot be null”错误,所以我假设before_save 没有被调用。我不知道为什么。我什至尝试过使用 before_save 过滤器。这是我的代码:
require 'secure_resource/secure_resource_encryption'
class Database < ActiveRecord::Base
belongs_to :username_encryption, :class_name => "Encryption", :foreign_key => :username_encryption_id
belongs_to :password_encryption, :class_name => "Encryption", :foreign_key => :password_encryption_id
# Virtual attribute to retrieve the decrypted username.
def username
if self.username_encryption.nil?
return nil
end
begin
return self.username_encryption.encryption
rescue SecureResourceError
raise SecureResourceError
end
end
# Provides a way to reset the username.
def username=(username)
if self.username_encryption.nil?
self.username_encryption = Encryption.new
self.username_encryption.encryption = username
end
end
# Virtual attribute to retrieve the decrypted password.
def password
if password_encryption.nil?
return nil
end
begin
return password_encryption.encryption
rescue SecureResourceError
raise SecureResourceError
end
end
# Provides a way to reset the password.
def password=(password)
if self.password_encryption.nil?
self.password_encryption = Encryption.new
self.password_encryption.encryption = password
end
end
def before_save
p 'ZZZZZZZZZZZZZZZ'
p self.user_id.to_s + ' ZZZZZZ'
p 'ZZZZZZZZZZZZZZZ'
self.username_encryption.user_id = self.user_id
self.username_encryption.save
self.username_encryption_id = self.username_encryption.id
self.password_encryption.user_id = self.user_id
self.password_encryption.save
self.password_encryption_id = self.password_encryption.id
end
end
【问题讨论】:
标签: ruby-on-rails validation activerecord callback