【发布时间】:2017-05-07 17:36:22
【问题描述】:
我有一个如下所示的 JSON 数组。我只想打印名称的值。但是我得到了未定义的索引名称并获得了 name 的值。下面是我的 json。
[{"docId":{"id":"57dd70252a896558e573a0c8"},"docProfile":{"name":"gowtham","gender":null,"email":null,"mobile":"7406339908"},"docLocalInfo":{"username":"gowtham","otp":934343,"newPasswordToken":null,"tempMobile":"","adminVerfiy":null},"privateInfo":{"mciNumber":null,"aadharNumber":null,"panNumber":null},"tempHospitals":[],"bankInfo":null,"signupSteps":{"accountCreated":true,"otpValidated":true},"notification":null,"hospitals":[],"address":null}]
我的代码
foreach($doc_array as $data => $mydata)
{
foreach($mydata as $key=>$val)
{
echo $val['name'];
}
}
如何从 docProfile 中获取 name 的值?任何帮助将不胜感激
【问题讨论】:
-
check like $val->name