在分组的父元素 XSLT 中分组子元素答案

【问题标题】：Grouping Child Elements within Grouped Parent Elements XSLT在分组的父元素 XSLT 中分组子元素
【发布时间】：2014-05-13 17:00:47
【问题描述】：

我正在使用for-each-group 组合 XML 元素，我遇到的问题是这些 XML 元素的子元素有自己的子元素。我也想结合子元素。

我的输入 XML 如下所示：

<Root>
   <Header>
   </Header>
   <Summary ID="1">
      <ID>1</ID>
      <Batch_Date>0228</Batch_Date>
      <Net_Sales_Amount>340.00</Net_Sales_Amount>
      <DATA_From_2>
         <Sales_Amount>340.00</_Sales_Amount>
      </DATA_From_2>
   </Summary>
   <Summary ID="1">
      <ID>1</ID>
      <Batch_Date>0228</Batch_Date>
      <Batch_Number>04002</Batch_Number>
      <Net_Sales_Amount>130.00</Net_Sales_Amount>
      <DATA_From_2>
         <Sales_Amount>130.00</Sales_Amount>
      </DATA_From_2>
      <DATA_From_8>
         <Invoice_Amount>20</Invoice_Amount>
         <Invoice_Number>123</Invoice_Number>
      </DATA_From_8>
      <DATA_From_8>
         <Invoice_Amount>15</Invoice_Amount>
         <Invoice_Number>456</Invoice_Number>
      </DATA_From_8>
   </Summary>
   <Summary ID="2">
      <ID>2</ID>
      <Batch_Date>0228</Batch_Date>
      <Net_Sales_Amount>40.00</Net_Sales_Amount>
      <DATA_From_2>
         <Sales_Amount>40.00</Sales_Amount>
      </DATA_From_2>
   </Summary>
   <Summary ID="2">
      <ID>2</ID>
      <Batch_Date>0228</Batch_Date>
      <Net_Sales_Amount>819.91</Net_Sales_Amount>
      <DATA_From_2>
         <Sales_Amount>734.91</Sales_Amount>
      </DATA_From_2>
      <DATA_From_5>
         <Sales_Amount>85.00</Sales_Amount>
      </DATA_From_5>
   </Summary>
</Root>

这是我的 XSLT 文件。我接近了我想要的输出，但它没有组合相同的子元素，而是将它们全部放在 Summary 元素中。

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output indent="yes" />

    <xsl:template match="/*">
        <xsl:copy>
            <Root>
                <xsl:for-each-group select="/Root/Summary" group-by="@ID">
                    <Summary ID="{@ID}">
                        <!-- Copy values that are the same -->
                        <xsl:sequence select="ID, Batch_Date"/>

                        <!-- Sum the amounts -->
                        <Net_Sales_Amount>
                            <xsl:value-of select="format-number(sum(current-group()/Net_Sales_Amount), '0.00')"/>
                        </Net_Sales_Amount>

                        <!-- Combine the record types in this Summary element -->
<!--                        <xsl:sequence select="DATA_From_2, DATA_From_3, DATA_From_5, DATA_From_8"/> -->

                        <xsl:for-each-group select="current-group()" group-by="DATA_From_2">
                            <Data_From_2>
                                <Sales_Amount>
                                    <xsl:value-of select="format-number(sum(current-group()/Data_From_2/Combined_Sales_Amount), '0.00')"/>
                                </Sales_Amount>
                            </Data_From_2>
                        </xsl:for-each-group>

                        <xsl:for-each-group select="current-group()" group-by="DATA_From_8">
                            <Data_From_8>
                                <Invoice_Amount>
                                    <xsl:value-of select="format-number(sum(current-group()/Data_From_8/Invoice_Amount), '0.00')"/>
                                </Invoice_Amount>
                                <Invoice_Number>
                                    <xsl:value-of select="current-group()/Data_From_8/Invoice_Number" separator=" | "/>
                                </Invoice_Number>
                            </Data_From_8>
                        </xsl:for-each-group>
                    </Summary>
                </xsl:for-each-group>

                <Header>
                </Header>
                <Footer>
                </Footer>
            </Root>
        </xsl:copy>
    </xsl:template>
</xsl:stylesheet>

这是我当前的输出：

<Root>
   <Summary ID="1">
      <ID>1</ID>
      <Batch_Date>0228</Batch_Date>
      <Net_Sales_Amount>470.00</Net_Sales_Amount>
      <Data_From_2>
         <Sales_Amount>0.00</Sales_Amount>
      </Data_From_2>
      <Data_From_2>
         <Sales_Amount>0.00</Sales_Amount>
      </Data_From_2>
      <Data_From_8>
         <Invoice_Amount>0.00</Invoice_Amount>
         <Invoice_Number/>
      </Data_From_8>
      <Data_From_8>
         <Invoice_Amount>0.00</Invoice_Amount>
         <Invoice_Number/>
      </Data_From_8>
   </Summary>
   <Summary ID="2">
      <ID>2</ID>
      <Batch_Date>0228</Batch_Date>
      <Net_Sales_Amount>859.91</Net_Sales_Amount>
      <Data_From_2>
         <Sales_Amount>0.00</Sales_Amount>
      </Data_From_2>
      <Data_From_2>
         <Sales_Amount>0.00</Sales_Amount>
      </Data_From_2>
      <Data_From_2>
         <Sales_Amount>0.00</Sales_Amount>
      </Data_From_2>
   </Summary>
</Root>

XSLT 没有组合相同的 Data_From 元素，也没有正确填充值。

它应该是这样的：

<Root>
   <Summary ID="1">
      <ID>1</ID>
      <Batch_Date>0228</Batch_Date>
      <Net_Sales_Amount>470.00</Net_Sales_Amount>
      <Data_From_2>
         <Sales_Amount>470.00</Sales_Amount>
      </Data_From_2>
      <Data_From_8>
         <Invoice_Amount>35.00</Invoice_Amount>
         <Invoice_Number/>
      </Data_From_8>
   </Summary>
   <Summary ID="2">
      <ID>2</ID>
      <Batch_Date>0228</Batch_Date>
      <Net_Sales_Amount>859.91</Net_Sales_Amount>
      <Data_From_2>
         <Sales_Amount>771.91</Sales_Amount>
      </Data_From_2>
      <DATA_From_5>
         <Sales_Amount>85.00</Sales_Amount>
      </DATA_From_5>
   </Summary>
</Root>

XSLT 应该组合相似的元素（Data_from_2、Data_from_5 等）并将这些值相加。对于任何拼写错误或不正确的 XML，我深表歉意，我做了很多复制和粘贴。谢谢

【问题讨论】：

怎么<Summary Merchant_ID="{@Merchant_ID}">产生<Summary ID="1">
@vels4j - 这是一个复制粘贴错误。我经历并尝试使名称简单易懂。我现在修好了。

标签： xml xslt foreach grouping

【解决方案1】：

我认为以下是您想要的：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output indent="yes" />

    <xsl:template match="/*">
        <xsl:copy>
            <Root>
                <xsl:for-each-group select="/Root/Summary" group-by="@ID">
                    <Summary Merchant_ID="{@ID}">
                        <!-- Copy values that are the same -->
                        <xsl:sequence select="ID, Batch_Date"/>

                        <!-- Sum the amounts -->
                        <Net_Sales_Amount>
                            <xsl:value-of select="format-number(sum(current-group()/Net_Sales_Amount), '0.00')"/>
                        </Net_Sales_Amount>

                        <!-- Combine the record types in this Summary element -->
<!--                        <xsl:sequence select="DATA_From_2, DATA_From_3, DATA_From_5, DATA_From_8"/> -->

                        <xsl:for-each-group select="current-group()/*[starts-with(local-name(), 'DATA_')]" group-by="node-name(.)">
                           <xsl:apply-templates select="."/>
                         </xsl:for-each-group>

                    </Summary>
                </xsl:for-each-group>

                <Header>
                </Header>
                <Footer>
                </Footer>
            </Root>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="DATA_From_2 | DATA_From_5">
                            <xsl:copy>
                                <Sales_Amount>
                                    <xsl:value-of select="format-number(sum(current-group()/Sales_Amount), '0.00')"/>
                                </Sales_Amount>
                            </xsl:copy>
    </xsl:template>

    <xsl:template match="DATA_From_8">
                            <xsl:copy>
                                <Invoice_Amount>
                                    <xsl:value-of select="format-number(sum(current-group()/Invoice_Amount), '0.00')"/>
                                </Invoice_Amount>
                                <Invoice_Number>
                                    <xsl:value-of select="current-group()/Invoice_Number" separator=" | "/>
                                </Invoice_Number>
                            </xsl:copy>
    </xsl:template>
</xsl:stylesheet>

【讨论】：

写得很棒<Invoice_Number>123 | 456</Invoice_Number>