为什么计数器代码每次计数都添加额外的行？答案

【问题标题】：why counter code add extra line every count?为什么计数器代码每次计数都添加额外的行？
【发布时间】：2020-05-18 06:45:34
【问题描述】：

这段代码有什么问题每次向上或向下计数时都会添加额外的行我该如何防止这种情况以及为什么会发生这种情况？

def counter(start, stop):
    x = start
    if start > stop:
        return_string = "Counting down: "
        while x >= stop:
            return_string += str(x)
            x = x-1 
            if start != stop:
                return_string += ","
            print(return_string)
    else:
        return_string = "Counting up: "
        while x <= stop:
            return_string += str(x)
            x = x + 1 
            if start != stop:
                return_string += ","
            print(return_string)
    return return_string

print(counter(1, 10)) # Should be "Counting up: 1,2,3,4,5,6,7,8,9,10"
print(counter(2, 1)) # Should be "Counting down: 2,1"
print(counter(5, 5)) # Should be "Counting up: 5"

【问题讨论】：

“每次向上或向下计数时添加额外的行”。每次循环打印。你看他们有关系吗？
只需删除函数中的print 语句。您可能还想return return_string.rstrip(',') 修剪尾随逗号。

标签： python for-loop while-loop counter

【解决方案1】：

def counter(start, stop):
    x = start
    if start > stop:
        return_string = "Counting down: "
        while x >= stop:
            return_string += str(x)
            if x != stop:
                return_string += ","
            x = x - 1

    else:
        return_string = "Counting up: "
    while x <= stop:
        return_string += str(x)
        if x != stop:
            return_string += ","
        x = x + 1

    return return_string

【讨论】：

虽然这段代码 sn-p 可以解决问题，但including an explanation 确实有助于提高帖子的质量。请记住，您是在为将来的读者回答问题，而这些人可能不知道您提出代码建议的原因。

【解决方案2】：

#这会起作用

def counter(start, stop):
    x = start
    if start > stop:
        return_string = "Counting down: "
        while x >= stop:
            return_string += str(x)
                if x != stop :
                    return_string += ","
                x = x - 1
        
    else:
         return_string = "Counting up: "
         while x <= stop:
             return_string += str(x)
             if x != stop:
                   return_string += ","
             x = x + 1
        
    return return_string

【讨论】：

【解决方案3】：

使用这个：

def counter(start, stop):
x = start
if start > stop:
    return_string = "Counting down: "
    while x >= stop:
        return_string += str(x)
        x = x-1
        if x >= stop:
            return_string += ","
else:
    return_string = "Counting up: "
    while x <= stop:
        return_string += str(x)
        x = x + 1
        if x <= stop:
            return_string += ","
return return_string

【讨论】：

【解决方案4】：

def counter(start, stop):
x = start
if start > stop:
    return_string = "Counting down: "
    while x >= stop:
        return_string += str(x)
        if x != stop :
            return_string += ","
        x -= 1
else:
    return_string = "Counting up: "
    while x <= stop:
        return_string += str(x)
        if x != stop:
            return_string += ","
        x += 1
return return_string

print(counter(1, 10)) # Should be "Counting up: 1,2,3,4,5,6,7,8,9,10"
print(counter(2, 1)) # Should be "Counting down: 2,1"
print(counter(5, 5)) # Should be "Counting up: 5"

【讨论】：

虽然这段代码 sn-p 可以解决问题，including an explanation 确实有助于提高您的帖子质量。请记住，您是在为将来的读者回答问题，而这些人可能不知道您提出代码建议的原因。

【解决方案5】：

您可以在此处使用此代码。这将打印出不带逗号的结果。

def counter(start, stop):
x = start
if x > stop:
    return_string = "Counting down: "
    while x >= stop:
        return_string += str(x)
        x = x-1
        if start != stop:
            return_string += ","
            return_string.rstrip(',')
else:
    return_string = "Counting up: "
    while x <= stop:
        return_string += str(x)
        x = x + 1
        if start != stop:
            return_string += ","
return return_string.rstrip(',')

【讨论】：

【解决方案6】：

这是一个：

def counter(start, stop):
    x = start
    if start>stop:

        return_string = "\"Counting down: "
        while x >= stop:
            return_string += str(x)
            x=x-1
            if x>=stop:
                return_string += ","
        return_string += '"'
    else:
        return_string = "\"Counting up: "
        while x <= stop:
            return_string += str(x)
            x=x+1
            if x<=stop:
                return_string += ","
        return_string += '"'
    return return_string

【讨论】：

【解决方案7】：

def counter(start, stop):
    x = start 
    if x>stop:
        return_string = "Counting down: "
        while x >= stop:
            return_string += str(x) 
        if x>stop:
            return_string += "," 
            x = x - 1
        else:
            return_string = "Counting up: " 
            while x <= stop: 
                return_string += str(x) 
                if x<stop:
                    return_string += "," 
                    x = x + 1
        return return_string

【讨论】：

【解决方案8】：

使用这个：

def counter(start, stop):
    x = start
    if start > stop:
        return_string = "Counting down: "
        while x >= stop:
            return_string += str(x)
            x = x-1
            if start != stop:
                return_string += ","
        print(return_string)
    else:
        return_string = "Counting up: "
        while x <= stop:
            return_string += str(x)
            x = x + 1
            if start != stop:
                return_string += ","
        print(return_string)
    return return_string

【讨论】：