计算文件每一行的每个单词的字符数

Question

此代码将打印文本文件中的总行数、总字数和总字符数。它工作正常并提供预期的输出。但我想计算每行中的字符数并像这样打印：-

Line No. 1 has 58 Characters
Line No. 2 has 24 Characters

代码：-

import string
def fileCount(fname):
    #counting variables
    lineCount = 0
    wordCount = 0
    charCount = 0
    words = []

    #file is opened and assigned a variable
    infile = open(fname, 'r')

    #loop that finds the number of lines in the file
    for line in infile:
        lineCount = lineCount + 1
        word = line.split()
        words = words + word

    #loop that finds the number of words in the file
    for word in words:
        wordCount = wordCount + 1
        #loop that finds the number of characters in the file
        for char in word:
            charCount = charCount + 1
    #returns the variables so they can be called to the main function        
    return(lineCount, wordCount, charCount)

def main():
    fname = input('Enter the name of the file to be used: ')
    lineCount, wordCount, charCount = fileCount(fname)
    print ("There are", lineCount, "lines in the file.")
    print ("There are", charCount, "characters in the file.")
    print ("There are", wordCount, "words in the file.")
main()

作为

for line in infile:
    lineCount = lineCount + 1 

正在计算整行，但是如何为该操作取每一行？ 我正在使用 Python 3.X

Answer 1

将所有信息存储在字典中，然后通过密钥访问。

def fileCount(fname):
    #counting variables
    d = {"lines":0, "words": 0, "lengths":[]}
    #file is opened and assigned a variable
    with open(fname, 'r') as f:
        for line in f:
            # split into words
            spl = line.split()
            # increase count for each line
            d["lines"] += 1
            # add length of split list which will give total words
            d["words"] += len(spl)
            # get the length of each word and sum
            d["lengths"].append(sum(len(word) for word in spl))
    return d

def main():
    fname = input('Enter the name of the file to be used: ')
    data = fileCount(fname)
    print ("There are {lines} lines in the file.".format(**data))
    print ("There are {} characters in the file.".format(sum(data["lengths"])))
    print ("There are {words} words in the file.".format(**data))
    # enumerate over the lengths, outputting char count for each line
    for ind, s in enumerate(data["lengths"], 1):
        print("Line: {} has {} characters.".format(ind, s))
main()

该代码仅适用于由空格分隔的单词，因此您需要牢记这一点。

Answer 2

定义您希望计数的允许字符的set，然后您可以使用len 获取大部分数据。
下面，我选择了字符集：

['!', '"', '#', '$', '%', '&', "'", '(', ')', '*', '+', ', ', '-', '.', '/', '0', '1', '2', '3', '4', '5', '6', '7', '8', '9'、':'、';'、''、'?'、'@'、'A'、'B'、'C'、'D'、'E '，'F'，'G'，'H'，'I'，'J'，'K'，'L'，'M'，'N'，'O'，'P'，'Q'， 'R'、'S'、'T'、'U'、'V'、'W'、'X'、'Y'、'Z'、'['、'\'、']'、'^ '，'_'，'`'，'a'，'b'，'c'，'d'，'e'，'f'，'g'，'h'，'i'，'j'， 'k'、'l'、'm'、'n'、'o'、'p'、'q'、'r'、's'、't'、'u'、'v'、'w '、'x'、'y'、'z'、'{'、'|'、'}'、'~']

#Define desired character set
valid_chars = set([chr(i) for i in range(33,127)])
total_lines = total_words = total_chars = 0
line_details = []

with open ('test.txt', 'r') as f:
    for line in f:
        total_lines += 1
        line_char_count = len([char for char in line if char in valid_chars])
        total_chars += line_char_count
        total_words += len(line.split())
        line_details.append("Line %d has %d characters" % (total_lines, line_char_count))

print ("There are", total_lines, "lines in the file.")
print ("There are", total_chars, "characters in the file.")
print ("There are", total_words, "words in the file.")
for line in line_details:
    print (line)

Answer 3

我的任务是创建一个打印一行中字符数的程序。

作为一个编程菜鸟，我发现这非常困难:(。

这是我想出的，以及他的回应 -

这是程序的核心部分：

with open ('data_vis_tips.txt', 'r') as inFile:
    with open ('count_chars_per_line.txt', 'w') as outFile:
        chars = 0
            for line in inFile:
                line = line.strip('\n')
                chars = len(line)
                outFile.write(str(len(line))+'\n')

可以简化为：

with open ('data_vis_tips.txt', 'r') as inFile:
    for line in inFile:
        line = line.strip()
        num_chars = len(line)
        print(num_chars)

请注意，strip() 函数的参数不是必需的；它默认去除空格，'\n' 是空格。

Answer 4

这是一个使用内置 collections.Counter 的更简单版本，这是一个专门计算其输入的字典。我们可以使用Counter.update() 方法在每一行中插入所有单词（唯一或非唯一）：

from collections import Counter

def file_count_2(fname):

    line_count = 0
    word_counter = Counter()

    infile = open(fname, 'r')
    for line in infile:
        line_count += 1
        word_counter.update( line.split() )

    word_count = 0
    char_count = 0

    for word, cnt in word_counter.items():
        word_count += cnt
        char_count += cnt * len(word)

    print(word_counter)

    return line_count, word_count, char_count

注意事项：

• 我对此进行了测试，它为您的代码提供了相同的计数
• 它会更快，因为您没有迭代地附加到列表words（最好只散列唯一的单词并存储它们的计数，这就是 Counter 所做的），也不需要迭代和递增charCount 每次我们看到一个单词的出现。
• 如果你只想要word_count 而不是char_count，你可以直接取word_count = sum(word_counter.values()) 而无需遍历word_counter