嵌套循环以在 php 中显示来自 JSON 数组的数据

Question

首先，让我告诉你，我是 PHP 新手，我已经搜索以了解我想要做什么，但找不到任何解决方案，这就是我在这里发帖的原因。对于专家开发人员来说，我的问题可能看起来很简单，但由于它是一个帮助平台，人们根据他们的专业知识发布他们的问题，所以我也是。如果它伤害了任何专家程序员 EGO，请不要关闭，因为任何善良的程序员都可以看到并帮助我。谢谢

我有一个 JSON 数组，它有多个记录

{"status": "ok", "items": [{"fullname": ["John Doe"], "current_street": "458 moh Hl Z,Jnm, MK M228", "previous_addresses": ["JHt Park Mn, VLK KOL, IU B581", "000 BVH L #5P,BGH, PL3 J210"], "cellphones": ["(000) 000-0001", "(000) 000-0002", "(000) 000-0003", "(000) 000-0004", "(000) 000-0005"], "landlines": [], "emails": [], "url": "https://www.example.com/JN1"}, {"fullname": ["John Doe 2"], "current_street": "000 BVH L #5P,BGH, PL J210", "previous_addresses": ["000 BVH L #5P,BGH, PL1 J210", "000 BVH L #5P,BGH, PL2 J210", "000 BVH L #5P,BGH, PL3 J210", "000 BVH L #5P,BGH, PL4 J210", "000 BVH L #5P,BGH, PL5 J210", "000 BVH L #5P,BGH, PL5 J210", "000 BVH L #5P,BGH, PL6 J210"], "cellphones": [], "landlines": ["(000) 000-0001", "(000) 000-0002", "(000) 000-0003", "(000) 000-0004", "(000) 000-0005"], "emails": ["email1@example.com", "email2@example.com"], "url": "https://www.example.com/JD3"}], "items_dropped": [], "stats": {"crawlera/delay/reset_backoff": 10, "crawlera/request": 10, "crawlera/request/method/GET": 10, "crawlera/response": 10, "crawlera/response/status/200": 10, "downloader/request_bytes": 5500, "downloader/request_count": 10, "downloader/request_method_count/GET": 10, "downloader/response_bytes": 81243, "downloader/response_count": 10, "downloader/response_status_count/200": 10, "elapsed_time_seconds": 3.511176, "finish_reason": "finished", "finish_time": "2020-05-11 18:56:49", "item_scraped_count": 9, "log_count/DEBUG": 19, "log_count/INFO": 12, "memusage/max": 66445312, "memusage/startup": 66445312, "request_depth_max": 1, "response_received_count": 10, "scheduler/dequeued": 10, "scheduler/dequeued/memory": 10, "scheduler/enqueued": 10, "scheduler/enqueued/memory": 10, "start_time": "2020-05-11 18:56:46"}, "spider_name": "friendsearch"}

我需要遍历它们以在 PHP 中回显每条记录，使一条记录可以包含多个 current_address、手机、固定电话值。

基于我的搜索和研究，我已经尝试过

$outputDetails = '{"status": "ok", "items": [{"fullname": ["John Doe"], "current_street": "458 moh Hl Z,Jnm, MK M228", "previous_addresses": ["JHt Park Mn, VLK KOL, IU B581", "000 BVH L #5P,BGH, PL3 J210"], "cellphones": ["(000) 000-0001", "(000) 000-0002", "(000) 000-0003", "(000) 000-0004", "(000) 000-0005"], "landlines": [], "emails": [], "url": "https://www.example.com/JN1"}, {"fullname": ["John Doe 2"], "current_street": "000 BVH L #5P,BGH, PL J210", "previous_addresses": ["000 BVH L #5P,BGH, PL1 J210", "000 BVH L #5P,BGH, PL2 J210", "000 BVH L #5P,BGH, PL3 J210", "000 BVH L #5P,BGH, PL4 J210", "000 BVH L #5P,BGH, PL5 J210", "000 BVH L #5P,BGH, PL5 J210", "000 BVH L #5P,BGH, PL6 J210"], "cellphones": [], "landlines": ["(000) 000-0001", "(000) 000-0002", "(000) 000-0003", "(000) 000-0004", "(000) 000-0005"], "emails": ["email1@example.com", "email2@example.com"], "url": "https://www.example.com/JD3"}], "items_dropped": [], "stats": {"crawlera/delay/reset_backoff": 10, "crawlera/request": 10, "crawlera/request/method/GET": 10, "crawlera/response": 10, "crawlera/response/status/200": 10, "downloader/request_bytes": 5500, "downloader/request_count": 10, "downloader/request_method_count/GET": 10, "downloader/response_bytes": 81243, "downloader/response_count": 10, "downloader/response_status_count/200": 10, "elapsed_time_seconds": 3.511176, "finish_reason": "finished", "finish_time": "2020-05-11 18:56:49", "item_scraped_count": 9, "log_count/DEBUG": 19, "log_count/INFO": 12, "memusage/max": 66445312, "memusage/startup": 66445312, "request_depth_max": 1, "response_received_count": 10, "scheduler/dequeued": 10, "scheduler/dequeued/memory": 10, "scheduler/enqueued": 10, "scheduler/enqueued/memory": 10, "start_time": "2020-05-11 18:56:46"}, "spider_name": "friendsearch"}';
$output = json_decode($outputDetails);

foreach ($output->items as $item){
  echo "Name: ".$item->fullname;
  echo "<br>";
}

但它向我显示了以下结果：

Name: Array
Name: Array

而我想要达到的目标是：

Name: John Doe
Current Address: 458 moh Hl Z,Jnm, MK M228
Previous Addresses: JHt Park Mn, VLK KOL, IU B581, 000 BVH L #5P,BGH, PL3 J210

Name: John Doe 2
Current Address: 000 BVH L #5P,BGH, PL J210
Previous Addresses: 000 BVH L #5P,BGH, PL1 J210, 000 BVH L #5P,BGH, PL2 J210, 000 BVH L #5P,BGH, PL3 J210, 000 BVH L #5P,BGH, PL4 J210, 000 BVH L #5P,BGH, PL5 J210, 000 BVH L #5P,BGH, PL5 J210, 000 BVH L #5P,BGH, PL6 J210

所以，首先我想循环显示每条记录，然后循环显示它们各自的属性。有什么帮助吗？谢谢

Answer 1

您构建 JSON 的方式并不完全正确。通过将字符串包装在方括号中，您已将 fullname 定义为数组。而不是["John Doe"]，只需使用"John Doe"。这将允许您使用 $item->fullname 返回名称。

如果要显示嵌套数组不同级别的值，则需要在结构的每个级别创建一个循环。

您下面的foreach 仅访问数组的第一级。

foreach ($output->items as $item){
  echo "Name: ".$item->fullname;
  echo "<br>";
}

如果您想遍历数组中的值（根据您的问题），请在其中添加另一个 foreach 语句：

foreach ($output->items as $item){
    echo "Current Address: " . $item->current_street;
    echo "Previous Addresses: ";
    foreach($item->previous_addresses as $address){
        echo $address;
    }
}

第二个foreach 在这种情况下是多余的，您可以使用implode 将数组显示为字符串，如下所示：

echo implode(",", $item->previous_addresses);

查看https://jsonlint.com/ 以格式化 JSON 以使其更具可读性。此外，还有一个名为 JSONView 的 Chrome 插件，如果您使用 API，它有助于在浏览器中查看输出。

Answer 2

在你的 json 你有

items":[
{
"fullname":[
"John Doe"
],

应该是

items":[
{
"fullname":"John Doe",

或者

echo "Name: ".$item->fullname[0];