1.顾名思义,您只能将其用于局部变量。
2.局部类型推断不能用于没有初始化器的变量
例如下面的代码将不起作用
案例 1:
var xyz = null;
^
(variable initializer is 'null')
案例 2:
var xyz;
^
(cannot use 'val' on variable without initializer)
案例 3:
var xyz = () -> { };
^
(lambda expression needs an explicit target-type)
3. var 不能在同一行实例化多个变量
更多细节可以找到herenullpointer 建议
var X=10,Y=20,Z=30 // this is not allowed
4:Var 作为参数
3.1 var would not be available for method parameters.
3.2 Var would not be available for constructor parameters.
3.3 Var would not be available for method return types.
3.4 Var would not be available for catch parameters.
4.不允许使用数组初始化器
更多细节可以找到here Nicolai 建议
var k = { 1 , 2 };
^
(array initializer needs an explicit target-type)
5.方法引用不允许
var someVal = this::getName;
error: cannot infer type for local variable nameFetcher
(method reference needs an explicit target-type)