如何将数组中的对象转换为特定格式答案

【问题标题】：How to convert the objects inside an array into a specific format如何将数组中的对象转换为特定格式
【发布时间】：2020-03-16 22:26:52
【问题描述】：

我有一个格式如下的 API：

[
   {
      "id": 4,
      "code": "IN",
      "name": "India",
      "recordVersion": "6CB5C760-E145-4FFA-AC63-FAF5F36B6C80",
      "updatedBy": "Sini "
   },
   {
      "id": 59,
      "code": "UK",
      "name": "United Kingdom",
      "recordVersion": "3512B084-8DB7-48F6-9E01-C0861E2A128D",
      "updatedBy": "sinju "
   }
]

我需要把它转换成这种格式：

localizedData = [ 
    { 
        text: "India", 
        value: 4 
    }, 
    { 
        text: "United Kingdom", 
        value: 59 
    }
];

我该怎么做？

【问题讨论】：

标签： javascript arrays json ecmascript-6 mapping

【解决方案1】：

假设您要将name 属性映射到text，并将id 属性映射到value。

const source = [
  {
    "id": 4,
    "code": "IN",
    "name": "India",
    "recordVersion": "6CB5C760-E145-4FFA-AC63-FAF5F36B6C80",
    "updatedBy": "Sini "
  },
  {
    "id": 59,
    "code": "UK",
    "name": "United Kingdom",
    "recordVersion": "3512B084-8DB7-48F6-9E01-C0861E2A128D",
    "updatedBy": "sinju "
  }
];

const localizedData = source.map(item => ({text: item.name, value: item.id}));

console.log(localizedData )

了解Array.prototype.map() 对您下次有帮助。

【讨论】：

【解决方案2】：

它会帮助你-----

             var results = data;
               var arr = [], item;
                 for (var i = 0, len = results.length; i < len; i++) {
                      item = results[i];
                      arr.push({username: item.username, description: item.description, 
                         name: 
                        item.name});
                               }

【讨论】：

【解决方案3】：

假设你的结果数组是：

const res =  { "id": 4, "code": "IN", "name": "India", "recordVersion": "6CB5C760-E145-4FFA-AC63-FAF5F36B6C80", "updatedBy": "Sini " }, { "id": 59, "code": "UK", "name": "United Kingdom", "recordVersion": "3512B084-8DB7-48F6-9E01-C0861E2A128D", "updatedBy": "sinju " } }

您需要做的就是：

const res2 = res.map(a => ({text: a.name, value: a.id}));

应该可以的

【讨论】：

小语法问题：res.map(a => ({text: a.name, value: a.id}) 否则将映射到未定义。

【解决方案4】：

你可以试试这个。

const data = [
  {
    "id": 4,
    "code": "IN",
    "name": "India",
    "recordVersion": "6CB5C760-E145-4FFA-AC63-FAF5F36B6C80",
    "updatedBy": "Sini "
  },
  {
    "id": 59,
    "code": "UK",
    "name": "United Kingdom",
    "recordVersion": "3512B084-8DB7-48F6-9E01-C0861E2A128D",
    "updatedBy": "sinju "
  }
];

const localizedData = [];

for(i=0;i< data.length;i++){
localizedData.push({text : data[i].name, value : data[i].id})
}

console.log(localizedData)

【讨论】：

【解决方案5】：

试试这个：

解决方案 1：

var jsonObj = [
   {
      "id": 4,
      "code": "IN",
      "name": "India",
      "recordVersion": "6CB5C760-E145-4FFA-AC63-FAF5F36B6C80",
      "updatedBy": "Sini "
   },
   {
      "id": 59,
      "code": "UK",
      "name": "United Kingdom",
      "recordVersion": "3512B084-8DB7-48F6-9E01-C0861E2A128D",
      "updatedBy": "sinju "
   }
];

jsonObj.map((obj) => {
	obj["value"] = obj["id"];
  obj["text"] = obj["name"];
  delete obj.id;
  delete obj.code;
  delete obj.name;
  delete obj.recordVersion;
  delete obj.updatedBy;
});

console.log(jsonObj);

解决方案 2：

const jsonObj = [
  {
    "id": 4,
    "code": "IN",
    "name": "India",
    "recordVersion": "6CB5C760-E145-4FFA-AC63-FAF5F36B6C80",
    "updatedBy": "Sini "
  },
  {
    "id": 59,
    "code": "UK",
    "name": "United Kingdom",
    "recordVersion": "3512B084-8DB7-48F6-9E01-C0861E2A128D",
    "updatedBy": "sinju "
  }
];

const res = [];

for (var i of jsonObj) {
  res.push({value : i.id, text : i.name});
}

console.log(res);

【讨论】：