【发布时间】:2020-09-28 11:10:49
【问题描述】:
这个想法是获取所有链接和响应 ID,隐藏非“活动”的内容。单击时,锚链接应该打开是相应的内容。
标记
<div class="navbar">
<nav>
<ul class="navTabs">
<li class="active">
<a href="#tab1">
Tab 1
</a>
</li>
<li>
<a href="#tab2">
Tab 2
</a>
</li>
<li>
<a href="#tab3">
Tab 3
</a>
</li>
</ul>
</nav>
</div>
<div class="navcontent">
<div class="content" id="tab1">
<h4>
Tab 1
</h4>
<p>Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod
tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam,
quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo
consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse
cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non
proident, sunt in culpa qui officia deserunt mollit anim id est laborum.</p>
</div>
<div class="content" id="tab2">
<h4>
Tab 2
</h4>
<p>
Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod
tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam,
quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo
consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse
cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non
proident, sunt in culpa qui officia deserunt mollit anim id est laborum.
</p>
</div>
<div class="content" id="tab3">
<h4>
Tab 3
</h4>
<p>
Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod
tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam,
quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo
consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse
cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non
proident, sunt in culpa qui officia deserunt mollit anim id est laborum.
</p>
</div>
</div>
脚本
$('ul.navTabs').each(function() {
var $active, $content, $links = $(this).find('a');
$active = $($links.filter('[href="' + location.hash + '"]')[0] || $links[0]);
$active.addClass('active');
$content = $($active[0].hash);
$links.not($active).each(function() {
$(this.hash).hide();
});
$(this).on('click', 'a', function(e) {
e.preventDefault();
$active.removeClass('active');
$content.hide();
$active = $(this);
$content = $(this.hash);
$active.addClass('active');
$content.show();
});
});
上面的脚本代码有效,挑战是将其重写到 ES6 中(我在下面做了,但没有按预期工作)。 Here 是一个 jsFiddle 代码来说明我面临的问题。
$("ul.navTabs > li").each((index, element) => {
// keep track of tabs and associated content
const anchorTag = $(element).find("a");
let active = anchorTag;
let content = anchorTag;
const links = anchorTag;
// if identifyUrlHash matches one of the links, use that as active tab
// if no match found, use first link as initial active tab
const identifyUrlHash = window.location.hash;
active = $(links.filter(`[href="${identifyUrlHash}"]`)[0] || links[0]);
active.addClass("active");
content = $(active[0].hash);
// hide the remaining content
links.not(active).each(element, (subindex, subelement) => {
$(subelement.hash).hide();
});
$(element).on("click", "a", (event) => {
event.preventDefault();
// old tab inactive
active.removeClass("active");
content.hide();
// update variables with new link and content
active = $(element);
content = $(element.hash);
// make tab active
element.addClass("active");
content.show();
});
});
【问题讨论】:
-
问题是什么?您发布的代码中有哪些不起作用?
-
这与 ES6 有什么特别的关系?你有 ES5 中的工作代码吗?
-
@Bergi 请查看 jsFiddle 代码以了解我遇到的问题。
-
不,请描述问题。什么没有按预期工作?
-
“在 ES6 中”具体是什么意思?您只想使用箭头功能?你想达到什么目的?定义“不起作用”。
标签: javascript jquery ecmascript-6