Python，for循环

Question

我有以下代码：

def get_asset_info(asset_list):

    import datetime

    today = datetime.datetime.today()
    day = today.strftime("%d")

    for i in range( len( asset_list )):
        raw_info = get_OHLC( asset_list[i], 15, get_server_time() )

        info = raw_info['result'][asset_list[i]]
        head = "time,open,high,low,close,vwap,volume,count"

        formatted_info = ""

        for i in range(len(info[0])):
            formatted_info = formatted_info + info[0][i] + ","

        file = open(asset_list[i]+"_"+day, "a")
        file.write(head + "\n")
        file.write(formatted_info)
        file.close()

它应该获取一些值，将其转换为字符串并将其写入文件，动态生成。 它不是这样工作的，所有值都放在同一个文件中。

如果我像下面这样更改代码的最后一部分，则会生成文件：

    formatted_info = str(info[0][0]) + "," + str(info[0][1]) + "," + str(info[0][2]) + "," + str(info[0][3]) + "," + str(info[0][4]) + "," + str(info[0][5]) + "," + str(info[0][6]) + "," + str(info[0][7])

    file = open(asset_list[i]+"_"+day, "a")
    file.write(head + "\n")
    file.write(formatted_info)
    file.close()

因此，正如我所见，问题出在我为生成字符串而创建的 for 循环中，但没有任何意义，因为生成文件的代码不在同一个循环中。

有什么想法吗？

Answer 1

for i in range( len( asset_list )):
    ...
    for i in range(len(info[0])):
        ...
    # now what do you think i is now?
    file = open(asset_list[i]+"_"+day, "a")

将第二个 i 更改为 j 应该可以解决问题：

for i in range( len( asset_list )):
    ...
    for j in range(len(info[0])):
        formatted_info = formatted_info + info[0][j] + ","

    file = open(asset_list[i]+"_"+day, "a")

甚至更好：

for i in range( len( asset_list )):
    ...
    for piece in info[0]:
        formatted_info = formatted_info + str(piece) + ","

    file = open(asset_list[i]+"_"+day, "a")

或者最终更好：

for i in range( len( asset_list )):
    ...
    formatted_info = ','.join(str(obj) for obj in info[0]) + ','
    file = open(asset_list[i]+"_"+day, "a")