将循环打印到文本文件中[重复]

Question

我希望能够将其打印到文本文件中，但是我环顾四周，无法弄清楚我需要做什么。

def countdown (n):
    while (n > 1):
        print('\n',(n), 'Bottles of beer on the wall,', (n), 'bottles of beer, take one down pass it around', (n)-1, 'bottles of beer on the wall.')
        n -= 1
        if (n == 2):
            print('\n',(n), 'Bottles of beer on the wall,', (n), 'bottles of beer, take one down pass it around', (n)-1, 'bottle of beer on the wall.')
        else:
            print ('\n',(n), 'Bottle of beer on the wall,', (n), 'bottle of beer, take one down pass it around no more bottles of beer on the wall.')

countdown (10)

Answer 1

而不是...

...
print('123', '456')

使用...

myFile = open('123.txt', 'w')
...
print('123', '456', file = myFile)
...
myFile.close() # Remember this out!

甚至……

with open('123.txt', 'w') as myFile:
    print('123', '456', file = myFile)

# With `with`, you don't have to close the file manually, yay!

我希望这对你有所启发！

Answer 2

为了更“正确”，它将被视为写入文本文件。您可以编写如下代码：

def countdown (n):
    # Open a file in write mode
    file = open( 'file name', 'w')
    while (n > 1):
        file.write('\n',(n), 'Bottles of beer on the wall,', (n), 'bottles of beer, take one down pass it around', (n)-1, 'bottles of beer on the wall.')
        n -= 1
        if (n == 2):
            file.write('\n',(n), 'Bottles of beer on the wall,', (n), 'bottles of beer, take one down pass it around', (n)-1, 'bottle of beer on the wall.')
        else:
            file.write('\n',(n), 'Bottle of beer on the wall,', (n), 'bottle of beer, take one down pass it around no more bottles of beer on the wall.')

    # Make sure to close the file, or it might not be written correctly.
    file.close()


countdown (10)