我想要基于对象键的单独对象值答案

【问题标题】：I would like separate Object values based on Object keys我想要基于对象键的单独对象值
【发布时间】：2021-09-12 14:54:14
【问题描述】：

需要将其他国家城市数据合并到单个对象中。我的输入如下

result = {
  "Bangalore": [
    {
      "Type": "Sale",
      "Date": "2021-07-10",
    },

    {
      "Type": "Product",
      "Date": "2021-07-03",
    }
  ],
  "Delhi": [
    {
      "Type": "Product",
      "Date": "2021-06-30",
    }
  ],
  "Chennai": [
    {
      "Type": "Production",
      "Date": "2021-06-30",
    },
    {
      "Type": "Production",
      "Date": "2021-07-11",
    },
  ],
  "Goa": [
    {
      "Type": "Product",
      "Date": "2021-06-30",
    }
  ],
    "sydney": [
    {
      "Type": "Product",
      "Date": "2021-06-30",
    }
  ],
    "melbourne": [
    {
      "Type": "Product",
      "Date": "2021-06-30",
    }
  ]

}

我有其他国家/地区城市数组如下

let arr = [
    "sydney",
    "melbourne"
  ]

我试过下面的sn-p它不起作用。

  let {sydney,melbourne,...final}=result;

let othercity = [...sydney,...melbourne]

console.log(final)

实际上，当我将变量传递给let {sydney,melbourne,...final} 时，它按预期工作。但我想动态传递这个变量sydney,melbourne。即'让 {...arr,...final}=result;'

预期输出结果：印度城市

{
  "Bangalore": [
    {
      "Type": "Sale",
      "Date": "2021-07-10"
    },
    {
      "Type": "Product",
      "Date": "2021-07-03"
    }
  ],
  "Delhi": [
    {
      "Type": "Product",
      "Date": "2021-06-30"
    }
  ],
  "Chennai": [
    {
      "Type": "Production",
      "Date": "2021-06-30"
    },
    {
      "Type": "Production",
      "Date": "2021-07-11"
    }
  ],
  "Goa": [
    {
      "Type": "Product",
      "Date": "2021-06-30"
    }
  ]
}

其他城市

{"othercities":[
  {
     "Type": "Product",
     "Date": "2021-06-30"
   },
   {
     "Type": "Product",
     "Date": "2021-06-30"
   }
]}

如何解决这个破坏性的概念。非常感谢您的回答

let result = {
  "Bangalore": [
    {
      "Type": "Sale",
      "Date": "2021-07-10",
    },

    {
      "Type": "Product",
      "Date": "2021-07-03",
    }
  ],
  "Delhi": [
    {
      "Type": "Product",
      "Date": "2021-06-30",
    }
  ],
  "Chennai": [
    {
      "Type": "Production",
      "Date": "2021-06-30",
    },
    {
      "Type": "Production",
      "Date": "2021-07-11",
    },
  ],
  "Goa": [
    {
      "Type": "Product",
      "Date": "2021-06-30",
    }
  ],
    "sydney": [
    {
      "Type": "Product",
      "Date": "2021-06-30",
    }
  ],
    "melbourne": [
    {
      "Type": "Product",
      "Date": "2021-06-30",
    }
  ]

}

let arr = [
    "sydney",
    "melbourne"
  ]
  
  let {sydney,melbourne,...final}=result;

let othercity = [...sydney,...melbourne]

  console.log(othercity)

console.log(final)

【问题讨论】：

请提供您的所有数据，以及您期望的结果。此外，不需要编写完整的对象，创建一个简单的示例来重现您的问题。
你到底想要什么？
"message": "SyntaxError: redeclaration of let arr", .. 首先，您的代码需要运行，其次，您希望final 是什么？
如果您不知道解构的具体工作原理，请不要使用解构。它只是语法糖。写出明确的长形式。
@Bergi 我更新了我的问题和预期结果

标签： javascript object ecmascript-6 destructuring

【解决方案1】：

你用的时候是对的

const { sydney, melbourne, ...indianCities } = result;

因为您要将结果累积到包含属性otherCities 的对象中，该属性是两个对象的数组，即sydney 和melbourne

const othercitiesObj = {
  otherCities: [...sydney, ...melbourne],
};

const result = {
  Bangalore: [
    {
      Type: "Sale",
      Date: "2021-07-10",
    },

    {
      Type: "Product",
      Date: "2021-07-03",
    },
  ],
  Delhi: [
    {
      Type: "Product",
      Date: "2021-06-30",
    },
  ],
  Chennai: [
    {
      Type: "Production",
      Date: "2021-06-30",
    },
    {
      Type: "Production",
      Date: "2021-07-11",
    },
  ],
  Goa: [
    {
      Type: "Product",
      Date: "2021-06-30",
    },
  ],
  sydney: [
    {
      Type: "Product",
      Date: "2021-06-30",
    },
  ],
  melbourne: [
    {
      Type: "Product",
      Date: "2021-06-30",
    },
  ],
};

let arr = ["sydney", "melbourne"];

const { sydney, melbourne, ...indianCities } = result;
const othercitiesObj = {
  otherCities: [...sydney, ...melbourne],
};

console.log(othercitiesObj);

已编辑：既然你想要动态城市

const result = {
  Bangalore: [
    {
      Type: "Sale",
      Date: "2021-07-10",
    },

    {
      Type: "Product",
      Date: "2021-07-03",
    },
  ],
  Delhi: [
    {
      Type: "Product",
      Date: "2021-06-30",
    },
  ],
  Chennai: [
    {
      Type: "Production",
      Date: "2021-06-30",
    },
    {
      Type: "Production",
      Date: "2021-07-11",
    },
  ],
  Goa: [
    {
      Type: "Product",
      Date: "2021-06-30",
    },
  ],
  sydney: [
    {
      Type: "Product",
      Date: "2021-06-30",
    },
  ],
  melbourne: [
    {
      Type: "Product",
      Date: "2021-06-30",
    },
  ],
};

let arr = ["sydney", "melbourne"];

const { sydney, melbourne, ...indianCities } = result;
const othercitiesObj = {
  otherCities: arr.flatMap((city) => result[city]),
};

console.log(othercitiesObj);

但是如果arr数组中不存在某个城市，那么你可以使用reduce

const result = {
  Bangalore: [
    {
      Type: "Sale",
      Date: "2021-07-10",
    },

    {
      Type: "Product",
      Date: "2021-07-03",
    },
  ],
  Delhi: [
    {
      Type: "Product",
      Date: "2021-06-30",
    },
  ],
  Chennai: [
    {
      Type: "Production",
      Date: "2021-06-30",
    },
    {
      Type: "Production",
      Date: "2021-07-11",
    },
  ],
  Goa: [
    {
      Type: "Product",
      Date: "2021-06-30",
    },
  ],
  sydney: [
    {
      Type: "Product",
      Date: "2021-06-30",
    },
  ],
  melbourne: [
    {
      Type: "Product",
      Date: "2021-06-30",
    },
  ],
};

let arr = ["sydney", "melbourne", "bhuna"];

const { sydney, melbourne, ...indianCities } = result;
const othercitiesObj = {
  otherCities: arr.reduce((acc, curr) => {
    if (result[curr]) acc = [...acc, ...result[curr]];
    return acc;
  }, []),
};

console.log(othercitiesObj);

【讨论】：

这个结果我已经得到了，但是我必须动态传递'arr'即数组并获取其他城市数据
@deckpk 我按照我的预期解决了这个问题 ` let arrRef: any = []; arr.map(item => { if (result[item]) { arrRef.push(...result[item]); 删除结果[item]; } });返回 arrRef； `
感谢您的帮助