JavaScript：删除属性===值的对象[重复]

Question

我有一个存储在 Redis 键中的 JSON 字符串。每当将用户添加到另一个用户列表时，我都会向此键添加一个对象。如何删除 name 属性与要删除的值匹配的对象。

[{"name":"srtyt1","wins":0,"losses":0,"levels":0,"color":1672960,"avatar":[]},
 {"name":"srtyt2","wins":0,"losses":0,"levels":0,"color":1672960,"avatar":[]}, 
 {"name":"srtyt3","wins":0,"losses":0,"levels":0,"color":1672960,"avatar":[]} ]

以上字符串是 Redis 的结果，我将其解析为 allFriends。我还有一个变量exFriend，它将保存名称属性之一的值。

有没有办法删除name属性等于"srtyt1"的对象？还是我需要重组我的数据？我在 Mozilla docs for maps 中看到了这个循环，但我猜它不适用于对象？

    let allFriends = JSON.parse(result);

    //iterate through all friends until I find the one to remove and then remove that index from the array
    for (let [index, friend] of allFriends) {
      if (friend.name === exFriend) {
        //remove the friend and leave
        allFriends.splice(index, 1);
        break;
      }
    }

Answer 1

如果我正确理解您的问题，您可以通过执行以下操作从数组中“过滤”需要您的 friend.name === exFriend 条件的项目：

const exFriend = 'srtyt1';
const inputArray = 
[{"name":"srtyt1","wins":0,"losses":0,"levels":0,"color":1672960,"avatar":[]},
 {"name":"srtyt2","wins":0,"losses":0,"levels":0,"color":1672960,"avatar":[]}, 
 {"name":"srtyt3","wins":0,"losses":0,"levels":0,"color":1672960,"avatar":[]} ];
 
 
 const outputArray = inputArray.filter(item => {
  
  return item.name !== exFriend;
 });
 
 console.log(outputArray);