类 (x) 的对象作为类 (y) 的属性

Question

我无法找到答案，因为我不知道如何表达。

我有一个类 Car() 和一个类 Owner()。我需要的是拥有一个“所有者”对象，作为我的 Car() 类的一个简单属性，因此一旦我实例化我的 Car() 对象，我就可以将它作为参数传递。

我的所有者（）类：

class Owner
{
    public Owner(string address){
        this.address = address;
    }
}

我的汽车（）类：

class Car
{
    public Car(object owner){ // what type to use?
        this.owner = owner; 
    }

    private object owner; // what type to use?
}

还有我的 Main() 类：

static void Main(string[] args){
    Owner owner1 = new Owner("street foo city bar");
    Car car1 = new Car(owner1); // this needs to work
}

显然，对属性使用“对象”类型并没有做到这一点。一旦我打印我得到'myProjectName.Owner'。提前谢谢你。

Answer 1

您可以编写如下代码，编写公共方法来返回您想要的对象。

 class Program
    {
        static void Main(string[] args)
        {
            Owner owner1 = new Owner("street foo city bar");
            Car car1 = new Car(owner1); // this needs to work

            Console.WriteLine("Car 1 owner address : " + car1.getOwner().getAddress());
            Console.ReadKey();


        }
    }


    class Car
    {
        private Owner owner;  // same here\
        public Car(Owner owner)
        { // use Owner class
            this.owner = owner;
        }

        public Owner getOwner() // write a public method to return owner
        {
            return this.owner;
        }


    }


    class Owner
    {

        private string address; // this 
        public Owner(string address)
        {

            this.address = address;
        }

        public string getAddress() // write a public method to return address
        {
            return this.address;
        }
    }

Answer 2

public class Car
{
    public Car(Owner owner)
    {
        this.Owner = owner;
    }

    //Since Owner is public, you don't have to create a getter method for this. i.e GetOwner()
    public Owner Owner;
}

public class Owner
{
    //Since address is private, you'll have to create a public getter for this
    private string address;

    public Owner(string address)
    {
        this.address = address;
    }

    //public getter for the address
    public string GetAddress()
    {
        return this.address;
    }
}

public class Main
{
    static void main(string[] args)
    {
        Owner owner1 = new Owner("street address");
        Car car1 = new Car(owner1);

        car1.Owner.GetAddress();
    }
}