提交表单后重定向到其他视图答案

【问题标题】：Redirect to other view after submitting form提交表单后重定向到其他视图
【发布时间】：2015-10-11 02:17:27
【问题描述】：

我有一份调查表。提交表单后，我想处理保存数据然后重定向到“成功”视图。我现在正在使用以下代码，但它只保留在当前 url 上，而我想转到 /success。我该怎么做？

@app.route('/surveytest', methods=['GET', 'POST'])
def surveytest():
    if request.method == 'GET':
        return render_template('test.html', title='Survey Test', year=datetime.now().year, message='This is the survey page.')
    elif request.method == 'POST':
        name = request.form['name']
        address = request.form['address']
        phone = request.form['phone']
        email = request.form['email']
        company = request.form['company']
        return render_template('success.html', name=name, address=address, phone = phone, email = email, company = company)

【问题讨论】：

标签： python redirect flask

【解决方案1】：

您有正确的目标：在处理表单数据后进行重定向是件好事。与其再次返回render_template，不如使用redirect。

from flask import redirect, url_for, survey_id

@app.route('/success/<int:result_id>')
def success(result_id):
     # replace this with a query from whatever database you're using
     result = get_result_from_database(result_id)
     # access the result in the tempalte, for example {{ result.name }}
     return render_template('success.html', result=result)

@app.route('/survey', methods=["GET", "POST"])
def survey():
    if request.method == 'POST':
        # replace this with an insert into whatever database you're using
        result = store_result_in_database(request.args)
        return redirect(url_for('success', result_id=result.id))

    # don't need to test request.method == 'GET'
    return render_template('survey.html')

重定向将由用户的浏览器处理，新 url 处的新页面将被加载，而不是在同一个 url 处呈现不同的模板。

【讨论】：