我只想从关联数组中打印一次重复的值

Question

我有一个关联数组，想打印所有部门，但部门不应该重复

<h3>2. List out all department  name </h3>
<div class="all">
</div>

我的 Jquery 代码是

var employee=[{"firstName":"Zahir","lastName":"Alam","Age":25,"Company":"Switchme","Role":"Developer","Department":"Tech","Head":{"Id":3,"Name":"Sourasis Roy"}},{"firstName":"Amith","lastName":"Manniken","Age":25,"Company":"Switchme","Role":"Developer","Department":"Tech","Head":{"Id":3,"Name":"Sourasis Roy"}},{"firstName":"Sourasis","lastName":"Roy","Age":28,"Company":"Switchme","Role":"CTO"},{"firstName":"Aditya","lastName":"Mishra","Age":29,"Company":"Switchme","Department":"Tech","Role":"CEO"},{"firstName":"Priti","lastName":"Lata","Age":24,"Company":"Switchme","Role":"HR"},{"firstName":"Sumita","lastName":"Nath","Age":24,"Company":"Switchme","Role":"HLA Head","Department":"Crm"},{"firstName":"Tarini","lastName":"Khanna","Age":22,"Company":"Switchme","Role":"Content Writer"},{"firstName":"Abhisek","lastName":"Soni","Age":23,"Company":"Switchme","Role":"HLA","Department":"Crm","Head":{"Id":5,"Name":"Sumita Nath"}},{"firstName":"Ankit","lastName":"Pump","Age":23,"Company":"Switchme","Role":"HLA","Department":"Crm","Head":{"Id":5,"Name":"Sumita Nath"}},{"firstName":"Pogo","lastName":"Laal","Age":23,"Company":"Switchme","Role":"Designer"},{"firstName":"Sabina","lastName":"Sekh","Age":28,"Company":"Switchme","Role":"HLA Head","Department":"Crm"},{"firstName":"Sanjay","lastName":"Poudal","Age":24,"Company":"Switchme","Role":"HLA Head","Department":"Crm","Head":{"Id":10,"Name":"Sabina Sekh"}}];

function unique(employee) {
    var result = [];
    $.each(list, function(i, e) {
        if ($.inArray(e, result) == -1) result.push(e);
    });
    return  $("div.all").text("result");
}

技术、客户关系管理 应该是输出

Answer 1

使用filter 和map 和Set 删除重复值：

var employee=[{"firstName":"Zahir","lastName":"Alam","Age":25,"Company":"Switchme","Role":"Developer","Department":"Tech","Head":{"Id":3,"Name":"Sourasis Roy"}},{"firstName":"Amith","lastName":"Manniken","Age":25,"Company":"Switchme","Role":"Developer","Department":"Tech","Head":{"Id":3,"Name":"Sourasis Roy"}},{"firstName":"Sourasis","lastName":"Roy","Age":28,"Company":"Switchme","Role":"CTO"},{"firstName":"Aditya","lastName":"Mishra","Age":29,"Company":"Switchme","Department":"Tech","Role":"CEO"},{"firstName":"Priti","lastName":"Lata","Age":24,"Company":"Switchme","Role":"HR"},{"firstName":"Sumita","lastName":"Nath","Age":24,"Company":"Switchme","Role":"HLA Head","Department":"Crm"},{"firstName":"Tarini","lastName":"Khanna","Age":22,"Company":"Switchme","Role":"Content Writer"},{"firstName":"Abhisek","lastName":"Soni","Age":23,"Company":"Switchme","Role":"HLA","Department":"Crm","Head":{"Id":5,"Name":"Sumita Nath"}},{"firstName":"Ankit","lastName":"Pump","Age":23,"Company":"Switchme","Role":"HLA","Department":"Crm","Head":{"Id":5,"Name":"Sumita Nath"}},{"firstName":"Pogo","lastName":"Laal","Age":23,"Company":"Switchme","Role":"Designer"},{"firstName":"Sabina","lastName":"Sekh","Age":28,"Company":"Switchme","Role":"HLA Head","Department":"Crm"},{"firstName":"Sanjay","lastName":"Poudal","Age":24,"Company":"Switchme","Role":"HLA Head","Department":"Crm","Head":{"Id":10,"Name":"Sabina Sekh"}}];
var repeated = [...new Set(employee.map(({ Department }) => Department).filter(Boolean))];
$("div.all").text(repeated.join(", "));

<script src="https://code.jquery.com/jquery-3.3.1.js"></script>
<h3>2. List out all department name </h3>
<div class="all"></div>

Answer 2

您可以通过map 数组获取Department，使用Set 获取唯一值。并使用filter 删除未定义

var employee=[{"firstName":"Zahir","lastName":"Alam","Age":25,"Company":"Switchme","Role":"Developer","Department":"Tech","Head":{"Id":3,"Name":"Sourasis Roy"}},{"firstName":"Amith","lastName":"Manniken","Age":25,"Company":"Switchme","Role":"Developer","Department":"Tech","Head":{"Id":3,"Name":"Sourasis Roy"}},{"firstName":"Sourasis","lastName":"Roy","Age":28,"Company":"Switchme","Role":"CTO"},{"firstName":"Aditya","lastName":"Mishra","Age":29,"Company":"Switchme","Department":"Tech","Role":"CEO"},{"firstName":"Priti","lastName":"Lata","Age":24,"Company":"Switchme","Role":"HR"},{"firstName":"Sumita","lastName":"Nath","Age":24,"Company":"Switchme","Role":"HLA Head","Department":"Crm"},{"firstName":"Tarini","lastName":"Khanna","Age":22,"Company":"Switchme","Role":"Content Writer"},{"firstName":"Abhisek","lastName":"Soni","Age":23,"Company":"Switchme","Role":"HLA","Department":"Crm","Head":{"Id":5,"Name":"Sumita Nath"}},{"firstName":"Ankit","lastName":"Pump","Age":23,"Company":"Switchme","Role":"HLA","Department":"Crm","Head":{"Id":5,"Name":"Sumita Nath"}},{"firstName":"Pogo","lastName":"Laal","Age":23,"Company":"Switchme","Role":"Designer"},{"firstName":"Sabina","lastName":"Sekh","Age":28,"Company":"Switchme","Role":"HLA Head","Department":"Crm"},{"firstName":"Sanjay","lastName":"Poudal","Age":24,"Company":"Switchme","Role":"HLA Head","Department":"Crm","Head":{"Id":10,"Name":"Sabina Sekh"}}];

var result = [...new Set(employee.map(o => o.Department))].filter(o => o);

console.log(result);