单击时如何禁用按钮？

Question

我是 python 新手，并且是自学的。我正在尝试制作一个名为“Mines”的简化扫雷游戏。这个游戏有一个 5 x 5 的按钮网格，带有随机数量的地雷。一切正常，除了一个问题。单击安全空间后，该按钮应被禁用，因此您无法获得更多积分。使用我的代码，我不知道该怎么做。

我已经尝试调用一个方法来禁用按钮，以及使用 DISABLED 命令。都没有奏效。我希望单击后禁用“白色”按钮，因为这些是安全空间。在理想情况下，我会在单击按钮时调用 disable() 方法并使用该方法禁用该按钮。

##Create the canvas of the board.
window = Tk ()
window.title("Mines Game")
window.geometry('819x655')
##Scoring function. The first box clicked awards 1 point, and after that each box is worth double your total points.
def score():
    global scores
    if (scores == 0):
        scores = scores + 1
        print ("Safe space hit! You have "   + str(scores) + " point.")
    else:
        scores = scores * 2 
        print ("Safe space hit! You have "   + str(scores) + " points.")
def squares():
    ##Main method of creating a 5x5 square of buttons.
    global scores
    scores = 0
    less_bombs = True
    r = -1
    c = 0
    x = 0
    if less_bombs:
        for i in range(5):
            r = r + 1
            for l in range(5):
                y = randint(0,25)
                if x == 5:
                    y = 10
                if y < 6:
                    btn = Button(window, bg = "red", command=end)
                    btn.grid(column = c,row = r)
                    #btn.grid(sticky="nesw")
                    btn.config(height = 8, width = 22)
                    x = x + 1
                else:
                    btn = Button(window, bg = "white", command=lambda:[score(),DISABLED])
                    btn.grid(column = c,row = r)
                    #btn.grid(sticky="nesw")
                    btn.config(height = 8, width = 22)
                c = c + 1
            c = 0
def end():
    ##This method creates the popup after you click a mine.
    end = Tk ()
    end.title ('Game Over!')
    end.geometry ('300x161')
    btn = Button(end, text ="Close game", command=close)
    btn.grid(column = 0,row = 0)
    #btn.grid(sticky="nesw")
    btn.config(height = 10, width = 20)
    btn = Button(end, text ="Reset game", command=lambda:[reset(),end.destroy()])
    btn.grid(column = 1,row = 0)
    #btn.grid(sticky="nesw"
    btn.config(height = 10, width = 20)
    if (scores == 1):
        print ("Game over! You hit a mine :(")
        print ("Your score for that game was "  + str(scores) + " point.")
    if (scores != 1):
        print ("Game over! You hit a mine :(")
        print ("Your score for that game was "  + str(scores) + " points.")
def disable():
    pass
def close():
    sys.exit()
def reset():
    squares()
squares()
window.mainloop()

我希望按钮在被点击后被禁用，但目前玩家可以根据需要多次点击按钮。

Answer 1

您可以通过更改白色Buttonss 的创建来修复它，如下面的所有大写字母所示。这为lambda 函数提供了btn 的默认值，它会更改循环的每次迭代（否则该函数将始终引用for 循环中创建的最后一个）。

def squares():
    """ Main method of creating a 5x5 square of buttons. """
    global scores
    scores = 0
    less_bombs = True
    r = -1
    c = 0
    x = 0
    if less_bombs:
        for i in range(5):
            r = r + 1
            for l in range(5):
                y = randint(0,25)
                if x == 5:
                    y = 10
                if y < 6:
                    btn = Button(window, bg="red", command=end)
                    btn.grid(column=c, row=r)
                    #btn.grid(sticky="nesw")
                    btn.config(height=8, width=22)
                    x = x + 1
                else:
                    btn = Button(window, bg="white")  ## REMOVE command= OPTION. ##
                    btn.grid(column=c, row=r)
                    #btn.grid(sticky="nesw")
                    btn.config(height=8, width=22, # USE command SHOWN BELOW. ##
                        command=lambda btn=btn: [score(), btn.config(state=DISABLED)])
                c = c + 1
            c = 0