我已经使用 DateComponentsFormatter 解决了这个问题,这可以为您节省大量使用不同语言本地化和处理复数等等的时间。
这可能看起来像很多代码,但我希望它会在未来节省我的时间。
import Foundation
class PeriodFormatter {
static var componentFormatter: DateComponentsFormatter {
let formatter = DateComponentsFormatter()
formatter.maximumUnitCount = 1
formatter.unitsStyle = .full
formatter.zeroFormattingBehavior = .dropAll
return formatter
}
static func format(unit: NSCalendar.Unit, numberOfUnits: Int) -> String? {
var dateComponents = DateComponents()
dateComponents.calendar = Calendar.current
componentFormatter.allowedUnits = [unit]
switch unit {
case .day:
dateComponents.setValue(numberOfUnits, for: .day)
case .weekOfMonth:
dateComponents.setValue(numberOfUnits, for: .weekOfMonth)
case .month:
dateComponents.setValue(numberOfUnits, for: .month)
case .year:
dateComponents.setValue(numberOfUnits, for: .year)
default:
return nil
}
return componentFormatter.string(from: dateComponents)
}
}
需要将 SKProduct 周期单位转换为 NSCalendarUnit
import StoreKit
@available(iOS 11.2, *)
extension SKProduct.PeriodUnit {
func toCalendarUnit() -> NSCalendar.Unit {
switch self {
case .day:
return .day
case .month:
return .month
case .week:
return .weekOfMonth
case .year:
return .year
@unknown default:
debugPrint("Unknown period unit")
}
return .day
}
}
您可以像这样从 SubscriptionPeriod 调用它:
import StoreKit
@available(iOS 11.2, *)
extension SKProductSubscriptionPeriod {
func localizedPeriod() -> String? {
return PeriodFormatter.format(unit: unit.toCalendarUnit(), numberOfUnits: numberOfUnits)
}
}
您可以像这样从 SKProductDiscount 依次调用。请注意,我暂时没有实现其他 PaymentMode。
import StoreKit
@available(iOS 11.2, *)
extension SKProductDiscount {
func localizedDiscount() -> String? {
switch paymentMode {
case PaymentMode.freeTrial:
return "Free trial for \(subscriptionPeriod.localizedPeriod() ?? "a period")"
default:
return nil
}
}
}