如何使用 AFNetworking 传递数组值？答案

【问题标题】：How to pass array value using AFNetworking?如何使用 AFNetworking 传递数组值？
【发布时间】：2016-07-28 06:02:05
【问题描述】：

现在我正在使用 APIS 进行 paypal 定期集成，我在以下 API 中面临请求格式问题。如何发送请求格式与同伴相同。

curl -v -k -X PATCH 'https://api.sandbox.paypal.com/v1/payments/billing-plans/P-94458432VR012762KRWBZEUA' \
    -H "Content-Type: application/json" \
    -H "Authorization: Bearer <Access-Token>" \
    -d '[
        {
            "path": "/",
            "value": {
                "state": "ACTIVE"
            },
            "op": "replace"
        }
    ]'

到目前为止，我已经尝试了以下代码

 NSDictionary *valueDic = @{@"state":@"ACTIVE"};
    NSDictionary *parametersDic = @{@"path":@"/",@"value":valueDic,@"op":@"replace"};
    NSMutableArray *parameterArray = [[NSMutableArray alloc] init];
    [parameterArray addObject:parametersDic];

    NSString *finalyToken = [[NSString alloc]initWithFormat:@"Bearer %@",strAccessToken];
    AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
    manager.requestSerializer = [AFJSONRequestSerializer serializer];
    manager.responseSerializer = [AFJSONResponseSerializer serializer];
    [manager.requestSerializer setValue:finalyToken forHTTPHeaderField:@"Authorization"];
    [manager.requestSerializer setValue:@"application/json+patch" forHTTPHeaderField:@"Content-Type"];
    [manager.responseSerializer.acceptableContentTypes setByAddingObject:@"application/json"];

    NSString *urlPatch = [NSString stringWithFormat:@"https://api.sandbox.paypal.com/v1/payments/billing-plans/%@",creditCardId];
    [manager PATCH:urlPatch parameters:parameterArray success:^(AFHTTPRequestOperation *operation, id responseObject){
         NSLog(@"JSON: %@", responseObject);
        [self recurringCreateBillingAgreement];
    }failure:^(AFHTTPRequestOperation *operation, NSError *error) {
       NSLog(@"Error: %@", error);

我已经创建了像上面这样的请求格式

(
{
    op = replace;
    path = "/";
    value =     {
        state = ACTIVE;
    };
}
)

但是，我收到以下错误

Error: Error Domain=com.alamofire.error.serialization.response Code=-1011 "Request failed: internal server error (500)" UserInfo=0x177155d0 {com.alamofire.serialization.response.error.response=<NSHTTPURLResponse: 0x1755c9b0> { URL: https://api.sandbox.paypal.com/v1/payments/billing-plans/P-1DT55351E261652436BZHSLA } { status code: 500, headers {
    "CORRELATION-ID" = 6bf7cbf78bb16;
    Connection = "close, close";
    "Content-Length" = 196;
    "Content-Type" = "text/xml;charset=UTF-8";
    Date = "Thu, 07 Apr 2016 11:19:08 GMT";
    "PROXY_SERVER_INFO" = "host=slcsbplatformapiserv3001.slc.paypal.com;threadId=368";
    "Paypal-Debug-Id" = "6bf7cbf78bb16, 6bf7cbf78bb16";
    Server = Apache;
    "Set-Cookie" = "X-PP-SILOVER=name%3DSANDBOX3.API.1%26silo_version%3D1880%26app%3Dplatformapiserv%26TIME%3D742524503; domain=.paypal.com; path=/; Secure; HttpOnly, X-PP-SILOVER=; Expires=Thu, 01 Jan 1970 00:00:01 GMT";
    Vary = Authorization;
} }, NSErrorFailingURLKey=https://api.sandbox.paypal.com/v1/payments/billing-plans/P-1DT55351E261652436BZHSLA, NSLocalizedDescription=Request failed: internal server error (500), com.alamofire.serialization.response.error.data=<3c6e7331 3a584d4c 4661756c 7420786d 6c6e733a 6e73313d 22687474 703a2f2f 6378662e 61706163 68652e6f 72672f62 696e6469 6e67732f 78666f72 6d617422 3e3c6e73 313a6661 756c7473 7472696e 6720786d 6c6e733a 6e73313d 22687474 703a2f2f 6378662e 61706163 68652e6f 72672f62 696e6469 6e67732f 78666f72 6d617422 3e6a6176 612e6c61 6e672e4e 756c6c50 6f696e74 65724578 63657074 696f6e3c 2f6e7331 3a666175 6c747374 72696e67 3e3c2f6e 73313a58 4d4c4661 756c743e>, NSUnderlyingError=0x1757d4c0 "Request failed: unacceptable content-type: text/xml"}

【问题讨论】：

上述错误解决使用了这行代码NSString* jsonString = @"[{\"path\": \"/\",\"value\": {\"state\": \"ACTIVE\"},\"op\": \"replace\"}]"; NSData *postBodyData = [NSData dataWithBytes: [jsonString UTF8String] length:[jsonString length]];

标签： ios objective-c paypal afnetworking

【解决方案1】：

您需要将 JSON 字符串作为一个参数发送。您可以如下创建数组的 JSON 字符串。

NSData *data = [NSJSONSerialization dataWithJSONObject:parameterArray options:0 error:nil];
NSString* jsonString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];

parameterArray 将是您的数组

现在使用jsonString 作为参数之一的值，以便将其发送到服务器。

【讨论】：