【发布时间】:2021-04-15 14:21:23
【问题描述】:
我正在练习我的 pygame 知识,但我在这里遇到了问题。我有两个矩形,但是当我运行程序时,其中一个在闪烁。我尝试交换zombi.appear() 和player.appear() 并注意到闪烁的矩形总是第二个(因此在下面的情况下它是player.appear())。所以我假设他们以某种方式互相打断。请帮我解决这个问题。
提前致谢!
import pygame
import random
# Variables
inProcess = True
width, height = 500, 500
red = (255, 0, 0)
blue = (0, 0, 255)
# Pygame Settings
pygame.init()
screen = pygame.display.set_mode([width, height])
clock = pygame.time.Clock()
class Mob:
def __init__(self, x, y, speed, type, color):
self.x = x
self.y = y
self.speed = speed
self.type = type
self.color = color
def render(self):
pygame.display.flip()
def appear(self):
pygame.draw.rect(screen, self.color, (self.x, self.y, 64, 64))
if self.type == 'player':
self.move_player()
if self.type == 'zombi':
self.move_zombi()
self.render()
def move_player(self):
keys = pygame.key.get_pressed()
if keys[pygame.K_w] and self.y > 0:
self.y -= self.speed
elif keys[pygame.K_s] and self.y < height - 64:
self.y += self.speed
elif keys[pygame.K_a] and self.x > 0:
self.x -= self.speed
elif keys[pygame.K_d] and self.x < width - 64:
self.x += self.speed
def move_zombi(self):
if self.y < 0 or self.y + 64 > height:
self.speed *= -1
self.y += self.speed
def main():
player = Mob(64, 64, 1, 'player', red)
zombi = Mob(256, 256, 2, 'zombi', blue)
while inProcess:
for event in pygame.event.get():
if event.type == pygame.QUIT:
quit()
screen.fill((255, 255, 255))
zombi.appear()
player.appear()
clock.tick(60)
main()
【问题讨论】:
标签: python python-3.x pygame render