Python/Pygame在离开窗口时使Pygame中的文本换行[重复]答案

【问题标题】：Python/Pygame make text in Pygame wrap when in leaves the window [duplicate]Python/Pygame在离开窗口时使Pygame中的文本换行[重复]
【发布时间】：2021-01-24 04:13:54
【问题描述】：

我有一个渲染文本的文本函数。函数如下

def textFunc(font,msg,color,x,y,center):
    text_render = font.render(msg,True,color)
    text_rect = text_render.get_rect()
    
    #If center is true, then the X,Y will be used as the center
    if center == True:
        text_rect.center = (x,y)
    else:
        text_rect = (x,y)
    game_display.blit(text_render,text_rect)

但是我的 msg 字符串太长它会呈现在窗口之外。

有没有办法让我的文本注册对我的窗口来说太长，因此在文本开头下方继续？与计算机如何自动完成类似

有点像这样：

【问题讨论】：

标签： python text pygame word-wrap

【解决方案1】：

没有自动解决方案。您必须自己实现文本换行并逐行分别逐字绘制文本。
幸运的是 PyGame wiki 为这个任务提供了一个函数。请参阅 PyGame wiki Simple Text Wrapping for pygame。

我扩展了函数并添加了一个额外的参数，它提供left或right对齐的文本，居中文本甚至阻止模式：

textAlignLeft = 0
textAlignRight = 1
textAlignCenter = 2
textAlignBlock = 3

def drawText(surface, text, color, rect, font, align=textAlignLeft, aa=False, bkg=None):
    lineSpacing = -2
    spaceWidth, fontHeight = font.size(" ")[0], font.size("Tg")[1]

    listOfWords = text.split(" ")
    if bkg:
        imageList = [font.render(word, 1, color, bkg) for word in listOfWords]
        for image in imageList: image.set_colorkey(bkg)
    else:
        imageList = [font.render(word, aa, color) for word in listOfWords]

    maxLen = rect[2]
    lineLenList = [0]
    lineList = [[]]
    for image in imageList:
        width = image.get_width()
        lineLen = lineLenList[-1] + len(lineList[-1]) * spaceWidth + width
        if len(lineList[-1]) == 0 or lineLen <= maxLen:
            lineLenList[-1] += width
            lineList[-1].append(image)
        else:
            lineLenList.append(width)
            lineList.append([image])

    lineBottom = rect[1]
    lastLine = 0
    for lineLen, lineImages in zip(lineLenList, lineList):
        lineLeft = rect[0]
        if align == textAlignRight:
            lineLeft += + rect[2] - lineLen - spaceWidth * (len(lineImages)-1)
        elif align == textAlignCenter:
            lineLeft += (rect[2] - lineLen - spaceWidth * (len(lineImages)-1)) // 2
        elif align == textAlignBlock and len(lineImages) > 1:
            spaceWidth = (rect[2] - lineLen) // (len(lineImages)-1)
        if lineBottom + fontHeight > rect[1] + rect[3]:
            break
        lastLine += 1
        for i, image in enumerate(lineImages):
            x, y = lineLeft + i*spaceWidth, lineBottom
            surface.blit(image, (round(x), y))
            lineLeft += image.get_width() 
        lineBottom += fontHeight + lineSpacing

    if lastLine < len(lineList):
        drawWords = sum([len(lineList[i]) for i in range(lastLine)])
        remainingText = ""
        for text in listOfWords[drawWords:]: remainingText += text + " "
        return remainingText
    return ""

最小示例： repl.it/@Rabbid76/PyGame-TextWrap

import pygame

pygame.init()
font = pygame.font.SysFont(None, 40)

msg = "Simple function that will draw text and wrap it to fit the rect passed.  If there is any text that will not fit into the box, the remaining text will be returned."
textRect = pygame.Rect(100, 100, 300, 300)

window = pygame.display.set_mode((500, 500))
run = True
while run:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False

    window.fill((255, 255, 255))
    pygame.draw.rect(window, (0, 0, 0), textRect, 1)
    drawTextRect = textRect.inflate(-5, -5)
    drawText(window, msg, (0, 0, 0), drawTextRect, font, textAlignBlock, True)
    pygame.display.flip()

【讨论】：