【发布时间】:2017-08-14 13:36:58
【问题描述】:
我想知道在转到 onPostExecute() 方法之前如何等待 servlet 的响应。
请提供解决方案。
编辑:编辑版本
Response responsed = null;
@Override
protected String doInBackground(String... strings) {
ArrayList<Farm> farmSend= dbFarm.getAllFarms();
String result = "";
OkHttpClient client = new OkHttpClient();
RequestBody postRequestBody = new FormBody.Builder()
.add("farms", new Gson().toJson(farmSend))
.add("dataToBeRetrieved", "getData")
.build();
Request request = new Request.Builder()
.url(new ipconfig().getIp() + "MobileFarm")
.post(postRequestBody)
.build();
try {
client.newCall(request).enqueue(new Callback() {
@Override
public void onFailure(Call call, IOException e) {
e.printStackTrace();
}
@Override
public void onResponse(Call call, Response response) throws IOException {
if (!response.isSuccessful()) throw new IOException("Unexpected code " + response);
responsed = response;
Headers responHeaders = response.headers();
for (int i = 0, size = responHeaders.size(); i < size; i++) {
Log.i("response: ", responHeaders.name(i) + ": " + responHeaders.value(i));
}
Log.i("response body: ", response.body().toString());
}
});
result = responsed.body().string();
} catch (IOException e) {
e.printStackTrace();
}
return result;
}
编辑:这是我的 servlet 代码。
protected void processRequest(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
int addCount = 0;
int updateCount = 0;
System.out.println("farmer input form mobile upload");
ArrayList<Farmer> farmers = new Gson().fromJson(request.getParameter("farmers"), new TypeToken<List<Farmer>>() {
}.getType());
for (int a = 0; a < farmers.size(); a++) {
if (a < new FarmerDAO().getListOfFarmers().size()) {
if (new FarmerDAO().updateFarmer(farmers.get(a))) {
updateCount++;
}
} else if (new FarmerDAO().registerFarmer(farmers.get(a))) {
addCount++;
} else {
System.out.println(farmers.get(a).getFarmerID() + " not added/updated");
}
}
System.out.println("farmer input count updated: " + updateCount);
System.out.println("farmer input count added: " + addCount);
response.getWriter().write(new Gson().toJson("farmer input completed"));
}
立即打印的唯一内容是“来自移动上传的农民输入”和“开始循环”。在收到任何响应之前,不会打印后续的打印行。
【问题讨论】:
-
不确定您的意思?您正在发送请求并获得响应。你还想等什么?
-
@MuratK。我应该等待 servlet 响应。但我收到 null,因为 servlet 尚未完成其任务的运行。
-
好吧,我想我明白你的意思了。看我的回答。
标签: java android servlets android-asynctask