【问题标题】:How to get database table data(oracle 11g) as an Json object & to display that Json object in Android?如何获取数据库表数据(oracle 11g)作为 Json 对象并在 Android 中显示该 Json 对象?
【发布时间】:2015-09-10 20:16:39
【问题描述】:

我正在尝试在 android 应用程序和 oracle DB 之间建立连接。我发现我必须创建一个 Web 服务,所以我开始编写一个 servlet,它将创建与数据库的连接并将数据作为 JSON 对象返回,该对象可以在 android 上解析。
首先我写了一个 servlet 来返回 HTML 格式的数据,这很简单,下面是我的 servlet 代码

package a.b.c;

import java.io.IOException;
import java.io.PrintWriter;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.ResultSet;
import java.sql.Statement;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class ServletDatabaseConnect extends HttpServlet  
{
    protected void doPost(HttpServletRequest req,HttpServletResponse res)throws ServletException,IOException
    {
        PrintWriter pw=res.getWriter();
        res.setContentType("text/html");        
        String tb=req.getParameter("table");    

        try
        {
             Class.forName("oracle.jdbc.driver.OracleDriver");
             Connection con=DriverManager.getConnection("jdbc:oracle:thin:@localhost:1521:XE","system","admin");
             Statement st=con.createStatement();
             System.out.println("connection established successfully...!!");     

             ResultSet rs=st.executeQuery("Select * from "+tb);

             pw.println("<table border=1>");
                 while(rs.next())
                 {
                     pw.println("<tr><td>"+rs.getInt(1)+"</td><td>"+rs.getString(2)+"</td>"+
                                      "<td>"+rs.getString(3)+"</td></tr>");
                 }
             pw.println("</table>");
             pw.close();
        }
        catch (Exception e){
            e.printStackTrace();
        }

    }
}

如何修改我的 servlet 代码以返回 JSON 对象格式的数据?

【问题讨论】:

    标签: java android json oracle servlets


    【解决方案1】:

    你必须使用Jackson将你的信息转换成json格式,这个动作叫做序列化,Jackson是完成这个任务的完美工具,你可以看一些例子here

    【讨论】:

    【解决方案2】:

    在这里我找到了我自己的答案,我使用了 JSON-simple-1.1.jar,它可以在 java2s.com 上免费获得

    following is my servlet code now
    
    package servlet.package1;
    
    import java.io.IOException;
    import java.sql.Connection;
    import java.sql.DriverManager;
    import java.sql.PreparedStatement;
    import java.sql.ResultSet;
    import java.sql.SQLException;
    import java.util.Enumeration;
    import java.util.logging.Level;
    import java.util.logging.Logger;
    
    import javax.servlet.ServletException;
    import javax.servlet.annotation.WebServlet;
    import javax.servlet.http.HttpServletRequest;
    import javax.servlet.http.HttpServlet;
    import javax.servlet.http.HttpServletResponse;
    
    import org.json.simple.JSONArray;
    import org.json.simple.JSONObject;
    
    
    
    
    @WebServlet("/ServletTalk")
    public class ServletTalk extends HttpServlet {
        private static final long serialVersionUID = 1L;
    
    
        public ServletTalk() {
            super();
            // TODO Auto-generated constructor stub
    
    
        }
    
     // <editor-fold defaultstate="collapsed" desc="HttpServlet methods. Click on the + sign on the left to edit the code.">
        /** 
         * Handles the HTTP <code>GET</code> method.
         * @param request servlet request
         * @param response servlet response
         * @throws ServletException if a servlet-specific error occurs
         * @throws IOException if an I/O error occurs
         */
        @Override
        protected void doGet(HttpServletRequest request, HttpServletResponse response)
                throws ServletException, IOException {
            //response.setContentType("text/html;charset=UTF-8");
            JSONObject json = new JSONObject();
    
    
            //ObjectOutputStream out = new ObjectOutputStream(response.getOutputStream());
            Enumeration paramNames = request.getParameterNames();
    
            String[] params = new String[2];
            int i = 0;
            while (paramNames.hasMoreElements()) {
                String paramName = (String) paramNames.nextElement();
    
    
                //System.out.println(paramName);
                String[] paramValues = request.getParameterValues(paramName);
                params[i] = paramValues[0];
    
                //System.out.println(params[i]);
                i++;
    
            }
    
            String sql = "SELECT LOGIN_ID, PASSWORD FROM SE_USER where LOGIN_ID=? and PASSWORD=?";
            Connection con = getConnection();
    
            try {
                PreparedStatement ps = con.prepareStatement(sql);
                ps.setString(1, params[0]);
                ps.setString(2, params[1]);
                ResultSet rs = ps.executeQuery();
                if (rs.next()) {
                    json.put("info", "success");
                    /*String sql1 = "SELECT uname, password FROM users";
                    PreparedStatement ps2=con.prepareStatement(sql1);
                    ResultSet rs2=ps2.executeQuery();
                    JSONArray arrayJSON=new JSONArray();
                    while(rs2.next())
                    {
                        JSONObject arrayObject = new JSONObject();
                        arrayObject.put("userName", rs2.getString("uname"));
                        arrayObject.put("passWord", rs2.getString("password"));
                        arrayJSON.add(arrayObject);
                    }
    
    
                    json.put("IDS",arrayJSON);*/
                } else {
                    json.put("info", "fail");
                }
            } catch (Exception e) {
                e.printStackTrace();
            }
            //System.out.println(json);
            response.setContentType("application/json");
            response.setCharacterEncoding("UTF-8");
            //json.put("info", disp);
            response.getWriter().write(json.toString());
        }
    
        /** 
         * Handles the HTTP <code>POST</code> method.
         * @param request servlet request
         * @param response servlet response
         * @throws ServletException if a servlet-specific error occurs
         * @throws IOException if an I/O error occurs
         */
        @Override
        protected void doPost(HttpServletRequest request, HttpServletResponse response)
                throws ServletException, IOException {
            doGet(request, response);
        }
    
        public static Connection getConnection() {
        Connection con = null;
        try {
            Class.forName("com.mysql.jdbc.Driver");//Mysql Connection
            //Class.forName("oracle.jdbc.driver.OracleDriver");//Oracle Connection
        } catch (ClassNotFoundException ex) {
            Logger.getLogger(ServletTalk.class.getName()).log(Level.SEVERE, null, ex);
        }
        try {
            con = DriverManager.getConnection("jdbc:mysql://localhost:8889/a9613246_mydata1", "root", "root");//mysql database
            //con = DriverManager.getConnection("jdbc:oracle:thin:@localhost:1521:xe", "hemabh_demo", "hemabh_demo");//oracle database
    
        } catch (SQLException ex) {
            Logger.getLogger(ServletTalk.class.getName()).log(Level.SEVERE, null, ex);
        }
        return con;
    }
    
    
    
    }
    

    返回的 JSON 格式不正确,但无需任何外部库(如 Gson 等)即可轻松解析。

    找到答案很有趣...谢谢

    【讨论】:

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