在字符串中省略 nil答案

【问题标题】：Omit nil in string在字符串中省略 nil
【发布时间】：2015-09-02 15:01:25
【问题描述】：

我正在练习 swift，目前正在编写一个简单的函数来显示当天的日程安排。 return 语句应该只包含 busyDay 如果它包含一个值。我希望这会自动完成，但事实并非如此。

func scheduleToday (date: String, day: String, numberOfMeetings: Int?) -> String {
    var meetingMessage = ""
    var busyDay: String!

    if var meetings = numberOfMeetings {
        if meetings > 4 {
           busyDay = "Today is a busy day!"
        }
       meetingMessage = "\(meetings) meetings"
    } else {
        meetingMessage = "no meetings today."
     }

    return "| \(date) - \(day) |   Good morning. \(busyDay) You have \(meetingMessage)."
}

如果numberOfMeetings 小于等于 4，则返回的字符串为：

// | 17th of June - Wedensday |   Good morning. nil You have 3 meetings.

【问题讨论】：

标签： string swift null return optional

【解决方案1】：

您可以在 if 中添加一条 else 语句，将 budyDay 设置为空字符串

if meetings > 4 {
    busyDay = "Today is a busy day!"
} else {
    busyDay = ""
}

【讨论】：

【解决方案2】：

您可以使用ternary operator，如果numberOfMeetings 小于或等于4，则分配空字符串，您的代码将是：

func scheduleToday (date: String, day: String, numberOfMeetings: Int?) -> String {
var meetingMessage = ""
var busyDay: String!

    if var meetings = numberOfMeetings {

        busyDay = meetings > 4 ? "\(meetings) meetings" : ""
        meetingMessage = "\(meetings) meetings"
    } else {
        meetingMessage = "no meetings today."
    }

    return "| \(date) - \(day) |   Good morning. \(busyDay) You have \(meetingMessage)."
}


let schedule = scheduleToday("1234", "8678678", 3)  // "| 1234 - 8678678 |   Good morning.  You have 3 meetings.""

【讨论】：