【发布时间】:2016-09-02 22:57:17
【问题描述】:
我不确定如何从具有值的方法返回对象的实例。有没有办法将 int 类型转换为我的对象类型? 这是我的一些说明:
/* Design a class named Location for locating a maximal value and its location in a
two-dimensional array. The class contains:
-Public double type data field maxValue that stores the maximal value in a two-dimensional
array
-Public int type data fields row and column that store the maxValue indices in a
two-dimensional array
Write a the following method that returns the location of the largest element in a two
dimensional array:
public static Location locateLargest(double[][] a)
The return value is an instance of Location. Write a test program that prompts the user to
enter a two-dimensional array and displays the location of the largest element in the
array. Here is a sample run:
Enter the number of rows and columns in the array: 3 4
Enter the array:
23.5 35 2 10
4.5 3 45 3.5
35 44 5.5 9.6
The location of the largest element is 45 at (1, 2) */
这是我的代码:
class Location {
public static double maxValue;
public static int row;
public static int column;
public static Location locateLargest(double[][] a) {
maxValue = a[0][0];
row = 0;
column = 0;
Location result = new Location();
for(int i = 0; i < a.length; i++) {
for(int j = 0; j < a[i].length; j++) {
if(a[i][j] > maxValue) {
maxValue = a[i][j];
row = i;
column = j;
if((i == a.length-1) && (j == a[i].length-1))
//Place indices of maxValue in result variable
}
else
continue;
}
}
return result;
}
}
我想我应该只为 Location 创建一个带有参数的构造函数,但我很不情愿,因为说明没有说要这样做。有没有其他方法可以做到这一点?谢谢
【问题讨论】:
-
是的,你可以添加一个参数化的构造函数并创建一个
Location。我不认为这是不正确的。不过你应该和你的讲师确认:) -
@TheLostMind 是的,我是这么认为的,谢谢
标签: java oop object types return