我在制作一个其属性是对象的对象时遇到问题（并且它们的属性是对象......等等）

Question

现在我正在编写代码作为处理数据的一种测试。我使用的数组比我实际要处理的数组短，我遇到了麻烦，我想我知道出了什么问题，但这有点像脑放屁，我实际上找不到问题。感谢您提供任何帮助，因此在此先感谢您。

if (!Object.prototype.hasOwnProperty('log')) {
  Object.defineProperty(Object.prototype, 'log', {
    get: function() {
      console.log(this);

    }
  });
}

if (!Object.prototype.hasOwnProperty('getProps')) {
  Object.defineProperty(Object.prototype, 'getProps', {
    get: function() {
      //console.log(Object.getOwnPropertyNames(this));
      return Object.getOwnPropertyNames(this);
    }
  });
}

function appendItem(list, item) {
  list.push(item);
}

var cities = ["Houston", "Dallas", "Rockwall", "Bossier", "Shreveport"];
var dates = ["monday", "monday", "monday", "monday", "monday"];
var states = ["Texas", "Texas", "Texas", "Louisiana", "Louisiana"];


function Setup(obj, sub, thisArg) {
  obj.forEach(function(key, index) {
    if ((this[key] == undefined)) {
      this[key] = [sub[index]];
    } else {
      appendItem(this[key], sub[index]);
    }
  }, thisArg);
  return obj;
}
var weather = {};
Setup(dates, states, weather);
weather.log;
Setup(states, cities, weather);
weather.log;

我想要的结果是可以做到这一点的：

weather = {monday:{Texas:["Houston", "Dallas", "Rockwall"], Louisiana:["Bossier", "Shreveport"]}};

但是以循环或函数的形式，因为当我弄清楚这一点时我将使用的实际数据要大得多。这是我得到的实际输出：

if (!Object.prototype.hasOwnProperty('log')) {
  Object.defineProperty(Object.prototype, 'log', {
    get: function() {
      console.log(this);

    }
  });
}

if (!Object.prototype.hasOwnProperty('getProps')) {
  Object.defineProperty(Object.prototype, 'getProps', {
    get: function() {
      //console.log(Object.getOwnPropertyNames(this));
      return Object.getOwnPropertyNames(this);
    }
  });
}

function appendItem(list, item) {
  list.push(item);
}

var cities = ["Houston", "Dallas", "Rockwall", "Bossier", "Shreveport"];
var dates = ["monday", "monday", "monday", "monday", "monday"];
var states = ["Texas", "Texas", "Texas", "Louisiana", "Louisiana"];


function Setup(obj, sub, thisArg) {
  obj.forEach(function(key, index) {
    if ((this[key] == undefined)) {
      this[key] = [sub[index]];
    } else {
      appendItem(this[key], sub[index]);
    }
  }, thisArg);
  return obj;
}
var weather = {};
Setup(dates, states, weather);
weather.log;
Setup(states, cities, weather);
weather.log;

Answer 1

您可以以不同的方式显示输出，例如将 vars 传递给 console.log()：

console.log（天气）；

或者通过漂亮的格式化：

console.log(JSON.stringify(weather));

如果你想继续，你应该注意输入数组中的数据如何， 如果它导致作为树或图。在分析您的情况后，一个可能的解决方案，如果输入数据是深度 = 3 的树类型，我建议是：

<script>
function append_item(list, item) {
  list.push(item);
}

var dates = ["monday", "monday", "monday", "monday", "monday"];
var states = ["Texas", "Texas", "Texas", "Louisiana", "Louisiana"];
var cities = ["Houston", "Dallas", "Rockwall", "Bossier", "Shreveport"];


function setup(obj, sub, this_arg) {
  obj.forEach(function(key, index) {
    if ((this[key] == undefined)) {
      this[key] = [sub[index]];
    } else if (!this[key].includes(sub[index])){
      append_item(this[key], sub[index]);
    }
  }, this_arg);
  return obj;
}


weather = {};
setup(dates, states, weather);

var sub_dict = {};
setup(states, cities, sub_dict);

var obj_values = Object.values(weather);
for (i=0; i<obj_values.length; i++){
    var x=obj_values[i];
    for (j=0; j<obj_values[i].length; j++){
        var y=obj_values[i][j];
        obj_values[i][j] = {};
        obj_values[i][j][y] = sub_dict[y];
    }
}
console.log(JSON.stringify(weather));
</script>

这段代码的输出是：

{"monday":[{"Texas":["Houston","Dallas","Rockwall"]},{"Louisiana":["Bossier","Shreveport"]}]}

（请注意，此格式可根据需要进行缩减，但格式略有不同）。

Answer 2

我无法弄清楚您的代码在做什么，但根据您的示例输出，您只需要一个循环，并将值链接在一起。

例如..

var cities = ["Houston", "Dallas", "Rockwall", "Bossier", "Shreveport"];
var dates = ["monday", "monday", "monday", "monday", "monday"];
var states = ["Texas", "Texas", "Texas", "Louisiana", "Louisiana"];


var weather = {};

for (var l = 0; l < cities.length; l += 1) {
  //day
  var d = weather[dates[l]] =
    weather[dates[l]] || {};  
  //state
  var s = d[states[l]] = 
    d[states[l]] || [];
  //cities
  s.push(cities[l]);
}

console.log(weather);