Javascript按值过滤嵌套对象属性

Question

我需要按属性值过滤嵌套对象。我知道以前有人问过类似的问题，但是对于将值存储在数组中的情况，我找不到解决方案。

在提供的代码示例中，我需要根据标签过滤对象。我想在标签数组中获取包含“a”和“b”的对象。

const input1 = {
    "0":{
        "id":"01",
        "name":"item_01",
        "tags":["a","b"],
    },
    "1":{
        "id":"02",
        "name":"item_02",
        "tags":["a","c","d"],
    },
    "2":{
        "id":"03",
        "name":"item_03",
        "tags":["a","b","f"],
    }
}
 
function search(input, key) {
   return Object.values(input).filter(({ tags }) => tags === key);
}

console.log(search(input1, "a"));

作为输出，我想收到休耕：

{
    "0":{
        "id":"01",
        "name":"item_01",
        "tags":["a","b"],
    },
    "2":{
        "id":"03",
        "name":"item_03",
        "tags":["a","b","f"],
    }
}

提前非常感谢！

Answer 1

function search(input, key) {
  Object.values(input).filter(x=>x.tags.includes(key))
}

Answer 2

由于您想保留对象结构，您应该使用Object.entries 而不是Object.values 并恢复为对象类型使用Object.fromEntries：

Object.fromEntries(Object.entries(input).filter(...))

要使其适用于多个键，请将every 与includes 结合使用作为谓词：

keys.every(key => tags.includes(key))

const input1 = {
    "0":{
        "id":"01",
        "name":"item_01",
        "tags":["a","b"],
    },
    "1":{
        "id":"02",
        "name":"item_02",
        "tags":["a","c","d"],
    },
    "2":{
        "id":"03",
        "name":"item_03",
        "tags":["a","b","f"],
    }
}
 
function search(input, keys) {
   return Object.fromEntries(
   Object.entries(input).filter(([, { tags }]) => keys.every(key => tags.includes(key)))
   )
   
}

console.log(search(input1, ["a", "b"]));

Answer 3

您可以使用Object.entries 将[key, value] 对作为数组的数组，然后您可以使用filter 过滤掉不包含key 数组中的元素的元素。最后，您可以使用reduce 生成单个值，即作为最终结果的对象

const input1 = {
  "0": {
    id: "01",
    name: "item_01",
    tags: ["a", "b"],
  },
  "1": {
    id: "02",
    name: "item_02",
    tags: ["a", "c", "d"],
  },
  "2": {
    id: "03",
    name: "item_03",
    tags: ["a", "b", "f"],
  },
};

function search(input, key) {
  return Object.entries(input)
    .filter(([, v]) => key.every((ks) => v.tags.includes(ks)))
    .reduce((acc, [k, v]) => {
      acc[k] = v;
      return acc;
    }, {});
}

console.log(search(input1, ["a", "b"]));

Answer 4

   function search(input, tagsToFind) {
  return Object.values(input).filter(inputItem => {
    tagsToFind = Array.isArray(tagsToFind) ? tagsToFind : [tagsToFind];
    let tagFound = false;
    for (const key in tagsToFind) {
      if (Object.prototype.hasOwnProperty.call(tagsToFind, key)) {
        const element = tagsToFind[key];
        if (inputItem.tags.indexOf(element) === -1) {
          tagFound = false;
          break;
        } else {
          tagFound = true;
        }
      }
    }

    return tagFound;
  })

  // ({ tags }) => tags === key);
}

}