【发布时间】:2014-02-04 12:15:58
【问题描述】:
我的 jquery 中有一个光滑的网格。它很好用,但似乎我无法创建动态 url,例如我需要获取另一列 (deviceId) 的值,然后将该值插入超链接 (/messagedetail?deviceId=1, /messagedetail?deviceId=2, / messagedetail?deviceId=3 等等...)。
var columns = [
{id: "device_id", name: "Device ID ", field: "device_id", headerCssClass:"cell-head", cssClass: "cell-row", width:170, resizable: false, selectable: true, sortable: true},
{id: "detail_link", name: "Details ", field: "detail_link", headerCssClass:"cell-head", formatter: linkFormatter = function ( row, cell, value, columnDef, dataContext ) {return '<a href=\"MessageDetail.jsp?deviceID='+device_id+'\"><img src=\"images/info.png\" style=\"\" alt=\"info\"></a>';}, cssClass: "cell-row", width:55, resizable: false, selectable: true, sortable: false}
];
但是,我似乎只能将值从列 defs 写入 url 链接(上面的代码),但是当我迭代为下面显示的行创建一些实际数据时,我实际上无法影响 url 链接本身下面(detail_link)并添加我想要添加的值。关于如何实现这一目标的任何想法?提前致谢。
$(function () {
var data = [];
for (var i = 0; i < 500; i++) {
data[i] = {
id: i+1,
num: i+1,
device_id: "asdf97sdfa98sdf7s987fsd987fs"+i,
detail_link: "<a href=\"MessageDetail.jsp?deviceID=' + somevar + '\"><img src=\"images/info.png\" style=\"\" alt=\"info\"></a>"
};
}
【问题讨论】:
标签: javascript jquery jquery-plugins slickgrid