获取对象 React Native 的列表属性答案

【问题标题】：Get list properties of object React Native获取对象 React Native 的列表属性
【发布时间】：2021-02-17 07:22:10
【问题描述】：

我不想获取数组中每个对象的 ID。
我有这个数组

[
  {
    "-ML8Lx8jOSv64Ecat611": {
      "category": "Automotive Parts & Accessories",
      "description": "I will be there at least but I don't know if I can help in any way I can",
      "item": "Apple Watch",
      "price": "429,99",
      "timestamp": "2020-11-02T21:28:11+07:00",
      "viewCount": 0
    }
  }
]

我期望得到的是

[
  {
      "category": "Automotive Parts & Accessories",
      "description": "I will be there at least but I don't know if I can help in any way I can",
      "item": "Apple Watch",
      "price": "429,99",
      "timestamp": "2020-11-02T21:28:11+07:00",
      "viewCount": 0
  }
]

【问题讨论】：

标签： arrays json firebase react-native firebase-realtime-database

【解决方案1】：

[
  {
    "-ML8Lx8jOSv64Ecat611": {
      "category": "Automotive Parts & Accessories",
      "description": "I will be there at least but I don't know if I can help in any way I can",
      "item": "Apple Watch",
      "price": "429,99",
      "timestamp": "2020-11-02T21:28:11+07:00",
      "viewCount": 0
    }
  }
]

在上面的示例中，您在一个需要唯一键的对象中使用了多个对象。您可以像这样简单地在数组中使用多个对象：

[
    {
      "category": "Automotive Parts & Accessories",
      "description": "I will be there at least but I don't know if I can help in any way I can",
      "item": "Apple Watch",
      "price": "429,99",
      "timestamp": "2020-11-02T21:28:11+07:00",
      "viewCount": 0
    },
    {
      "category": "Automotive Parts & Accessories",
      "description": "I will be there at least but I don't know if I can help in any way I can",
      "item": "Apple Watch",
      "price": "429,99",
      "timestamp": "2020-11-02T21:28:11+07:00",
      "viewCount": 0
    },
    .....
]

现在您可以通过数组索引访问每个对象。希望我的回答对你有帮助。

【讨论】：

不，这并不意味着我需要一些方法来削减对象的 ID。

【解决方案2】：

试试这个

var data = [
  {
    "-ML8Lx8jOSv64Ecat611": {
      "category": "Automotive Parts & Accessories",
      "description": "I will be there at least but I don't know if I can help in any way I can",
      "item": "Apple Watch",
      "price": "429,99",
      "timestamp": "2020-11-02T21:28:11+07:00",
      "viewCount": 0
    }
  },
  {
    "-NOa8Lx8jOSv64Ecat611": {
      "category": "Automotive Parts & Accessories",
      "description": "I will be there at least but I don't know if I can help in any way I can",
      "item": "Apple Watch",
      "price": "429,99",
      "timestamp": "2020-11-02T21:28:11+07:00",
      "viewCount": 0
    }
  }
]

console.log(data.map((item) => Object.values(item)[0]))

【讨论】：

【解决方案3】：

由于您想要在输出中的对象是嵌套的，因此您需要在 JSON 中循环两个级别：

let input = [
  {
    "-ML8Lx8jOSv64Ecat611": {
      "category": "Automotive Parts & Accessories",
      "description": "I will be there at least but I don't know if I can help in any way I can",
      "item": "Apple Watch",
      "price": "429,99",
      "timestamp": "2020-11-02T21:28:11+07:00",
      "viewCount": 0
    }
  }
];

let result = []
input.forEach(obj => {
  Object.keys(obj).forEach(key => {
    result.push(obj[key]);
  });
});

console.log(result);

【讨论】：