【发布时间】:2016-11-23 15:37:17
【问题描述】:
我正在使用 codeigniter 分页。我想通过 url 将一个值传递给控制器,通过它我可以根据条件获取数据
function index($offset) {
$type = $_GET['type'];
$this->load->library('pagination');
$config['base_url'] = base_url().'MarketPostingCenter/index';
$config['per_page'] = 15;
// $config['total_rows'] = 200;
if($type=="Agent"){
$data['market_posts'] = $this->model->getAllMarketPostsOfAgent('market_posting_tbl', $_SESSION['id'],$config['per_page'],$offset);
$config['total_rows'] = $this->model->getAllMarketPostsOfAgentCount('market_posting_tbl', $_SESSION['id']);
}elseif($type=="Underwriter"){
$data['market_posts'] = $this->model->getAllMarketPosts('market_posting_tbl',$_SESSION['id'],$config['per_page'],$offset);
$config['total_rows'] = $this->model->getAllMarketPostsCount('market_posting_tbl', $_SESSION['id']);
}
$this->pagination->initialize($config);
// print_r( $data['market_posts']);
$data['user'] = $this->model->getUser('profile_tbl', $_SESSION['id']);
$data['order'] ="";
$data['states'] = $this->model->getAllStates('states');
$this->load->view('MarketPostingCenter/marketPostingCenter.php',$data);
}
如何在不影响偏移值的情况下通过 url 传递 "?type=something"
【问题讨论】:
标签: php codeigniter url pagination get