如何将结构字段与C中的变量进行比较？ [复制]答案

【问题标题】：How to compare struct fields to variables in C? [duplicate]如何将结构字段与C中的变量进行比较？ [复制]
【发布时间】：2022-01-09 03:42:54
【问题描述】：

这是链表程序中删除功能的一部分。我正在尝试将当前结构节点的字段与用户读取的用于搜索的字段进行比较。我知道我的节点引用有效，因为我可以自己打印出当前字段，但我在 if 语句中与变量的比较没有。如何将当前字段与用户数据进行比较？谢谢

int deleteEmployee(void)
{
    char name[MAX_NAME_LENGTH];
    char gender[2];
    int age;
    char position[MAX_JOB_LENGTH];
    int placeInList = 0;

    Employee *current = employeeListHead;
    Employee *previous = employeeListHead;

    printf("Enter details of employee to delete: \n");
    printf("Name: \n");   
    scanf(" %100[^\n]s", name); 
    scanf("%*[^\n]%*c");

    printf("Gender: \n");
    scanf(" %1s", gender); 
    scanf("%*[^\n]%*c");

    printf("Age: \n");
    scanf(" %d", &age); 
    scanf("%*[^\n]%*c");

    printf("Title: \n");
    scanf(" %100[^\n]s", position); 
    scanf("%*[^\n]%*c");

    //while elements in list to search
    while(current != NULL)
    {

这个具体

        //handling a match on each iteration
        if (current->name == name && current->gender == gender && current->age == age && current->position == position)
        {
            printf("\nIs this the emplyee you'd like to delete? Please confirm (Y/N) %s %s %d %s \n\n", name, gender, age, position);
            char choice;
            scanf(" %c", &choice);

            //if delete is confirmed
            if (choice == 'Y' || choice == 'y')
            {   
                //if head of list
                if(current == employeeListHead)
                {
                    employeeListHead = current->next;
                    current = NULL;
                    return EXIT_SUCCESS;
                }
                //if tail
                else if(current->next == NULL)
                {   
                    //change previous nodes pointer
                    for (int i=0; current!=NULL && i < placeInList-1; i++)
                    {
                        previous->next = NULL;
                    }
                        
                    current = NULL;
                    
                    return EXIT_SUCCESS;
                }
                //if inside list
                else
                {
                    for (int i=0; current!=NULL && i < placeInList-1; i++)
                    {
                        previous->next = current->next;
                    }                    
                    current = NULL;
                    return EXIT_SUCCESS;
                }
                 
            }//end if yes selected to delete

            //if delete is confirmed
            if (choice == 'N' || choice == 'n')
            {
                printf("You selected N. Returning to main menu.");
                EXIT_FAILURE;
            }//end if no selected to delete

        }//end if a match

        //iterate to next set of nodes
        current = current->next;
        previous = previous->next;
        placeInList++;

    }//end iterating through list
    

    printf("Employee not found in system.\n");
    return EXIT_FAILURE;

    
}

【问题讨论】：

使用strcmp比较C中的字符串，而不是==

标签： c struct

【解决方案1】：

您需要使用strcmp 来比较字符串。当您编写current->name == name 时，您的程序只是比较两个指针的位置。（但是你没有给出name的定义，所以很难确定。）

尝试将所有字符串比较替换为：

0 == strcmp(current->name, name)

【讨论】：