【发布时间】:2019-12-13 04:16:53
【问题描述】:
我是一名自学成才的程序员,目前正在从事一个工作列表网站项目。我有一个带有搜索功能的工作列表页面。现在,用户可以按职位搜索,我想添加按关键字搜索的选项。
HTML
每个职位有 6 个属性:职位名称、职位位置、职位类型、职位行业和职位关键字。 job-keyword 是一个列表,因为作业可以有不同数量的关键字。
<div class="job-listing">
<div class="container">
<div class="job-number">
<h2>We Found <span id="number-jobs-total" class="text-secondary">214</span> Offers For <span>You</span> </h2>
</div>
<ul class="job-board">
<li class="job job-1">
<div class="job-title">
<h2>Process Engineer</h2>
</div>
<div class="job-location">
<p>Location: Naypyitaw</p>
</div>
<div class="job-type">
<p>Type: Full-Time</p>
</div>
<div class="job-date">
<p>Published on 07/19/2019</p>
</div>
<div class="job-industry">
<p>Engineering</p>
</div>
<ul class="job-keywords">
<li>Engineering</li>
<li>Science</li>
</ul>
</li>
<li class="job job-2">
<div class="job-title">
<h2>Chief Financial Officier</h2>
</div>
<div class="job-location">
<p>Location: Naypyitaw</p>
</div>
<div class="job-type">
<p>Type: Full-Time</p>
</div>
<div class="job-date">
<p>Published on 07/18/2019</p>
</div>
</li>
<li class="job job-3">
<div class="job-title">
<h2>Assistant CEO</h2>
</div>
<div class="job-location">
<p>Location: Naypyitaw</p>
</div>
<div class="job-type">
<p>Type: Part-Time</p>
</div>
<div class="job-date">
<p>Published on 07/18/2019</p>
</div>
</li>
<li class="job job-4">
<div class="job-title">
<h2>Front-End Developer</h2>
</div>
<div class="job-location">
<p>Location: Naypyitaw</p>
</div>
<div class="job-type">
<p>Type: Part-Time</p>
</div>
<div class="job-date">
<p>Published on 07/18/2019</p>
</div>
</li>
</ul>
<nav class="pagination-container">
<ul class="pagination">
<li><a href="javascript:void(0)">Previous</a></li>
<li><a href="javascript:void(0)">Next</a></li>
</ul>
</nav>
</div>
</div>
用于按标题搜索的 JS:
const search= document.querySelector(".skills");
const jobs = Array.from(document.querySelector(".job-board").children);
const filterJobs = term => {
jobs.filter(job =>{
const title = job.querySelector(".job-title").textContent.toLowerCase();
if(title.includes(term.toLowerCase()) || totalKeywords.includes(term.toLowerCase()) ){
job.style.display = "list-item";
} else{
job.style.display = "none";
}
});
};
search.addEventListener("keyup", e =>{
filterJobs(e.currentTarget.value.trim());
});
JS:我已经尝试过,我认为我并没有很远,但仍然没有工作
const search= document.querySelector(".skills");
const jobs = Array.from(document.querySelector(".job-board").children);
const filterJobs = term => {
jobs.filter(job =>{
const title = job.querySelector(".job-title").textContent.toLowerCase();
const keyword = job.querySelectorAll(".job-keywords li");
totalKeywords = [];
for(var i = 0 ; i < keyword.length ; i++){
totalKeywords.push(keyword[i].textContent);
}
console.log(totalKeywords);
if(title.includes(term.toLowerCase()) || totalKeywords.includes(term.toLowerCase()) ){
job.style.display = "list-item";
} else{
job.style.display = "none";
}
});
};
search.addEventListener("keyup", e =>{
filterJobs(e.currentTarget.value.trim());
});
【问题讨论】:
-
您好!你能给我们更多的问题细节吗?什么都没有发生或行为不是您想要的?
-
您能给我们举一个术语/关键字不起作用的例子吗?问题可能只是您在
for循环中忘记了.toLowerCase(),但也可能是includes没有按预期运行。
标签: javascript