【发布时间】:2021-04-11 08:16:37
【问题描述】:
“hdg-alert-popup”部分,如果状态处于活动状态,则必须是“hdg-alert-popup active” 而如果“hdg-button-login-container”按钮被点击它必须是“hdg-alert-popup”,我该怎么办?
import parse from 'html-react-parser';
import React, { useEffect, useState } from 'react';
const MessageError = (
titolo: string,
descrizione1: string,
descrizione2: string,
testoBottone: string,
) => {
const [active, setActive] = useState(true);
if (testoBottone == "") {
testoBottone = "Chiudi questo avviso";
}
return (
<section
className="hdg-alert-popup"
>
<div className="hdg-login-popup">
<div className="hdg-login-popup-container">
<div className="hdg-login-popup-content">
<h3 className="hdg-title">{parse(titolo)}</h3>
<p>
{descrizione1}
{descrizione2 != "" && <b>{descrizione2}</b>}
</p>
</div>
<div className="hdg-login-popup-error">
<div className="hdg-button-login-container"><a href="#" className="hdg-button-back">{testoBottone}</a></div>
</div>
</div>
</div>
</section>
);
};
export default MessageError;
【问题讨论】:
-
我投票结束这个问题,因为询问基本的反应语法
-
className={"hdg-alert-popup" + (active ? " active":"")}。别偷懒了,这是基本的反应语法。
标签: javascript html reactjs typescript jsx