在 VBA Excel 中查找、剪切和插入行以匹配借方和贷方的值

Question

我在 Sheet1 中有以下设置数据，并从第 4 行列 A 开始，其中第 3 行中的标题：

No  Date        Code              Name      Remarks   D e b i t   Cr e d i t
1   4/30/2015   004/AB/01/04/15   Anna      YES       40239.66    0.00
2   2/16/2015   028/AA/01/02/15   Andy      NO        0.00        2205.49
3   1/31/2015   021/DR/04/01/15   Jim       YES       167.60      0.00
4   7/14/2015   083/RF/01/07/15   Anna      YES       3822.60     0.00
5   8/6/2015    030/AB/01/08/15   Anna      NO        0.00        11267.96
6   1/15/2015   020/TY/01/01/15   Barry               0.00        5237.84
7   7/14/2015   024/HU/01/07/15   Anna      NO        0.00        3822.60
8   1/31/2015   039/JK/01/01/15             YES       0.00        1780.84
9   1/27/2015   007/ER/01/01/15   Jim       NO        5237.84     0.00
10  4/29/2015   077/FX/01/04/15   Barry     NO        0.00        40239.66
11  1/3/2015    001/OX/10/01/15   Andy      NO        33074.03    0.00
12  8/10/2015   001/PR/01/08/15   Nicholas            11267.96    0.00
13  10/31/2015  007/TX/09/10/15   Jim                 1780.84     0.00
14  2/28/2015   071/QR/01/02/15   Andy      YES       2205.49     0.00
15  1/7/2015    007/OM/02/01/15   Nicholas            8873.25     0.00

并且我需要根据借方和贷方的价值将上面的数据在同一张表中排列，没有特定的顺序，只要借方和贷方的值：x 和 y 后面是借方和贷方的值：y 和 x（最好是 x > y ) 其中不匹配的数据将放在排列表的底部。例如类似的东西：

No  Date        Code              Name      Remarks   D e b i t   Cr e d i t
14  2/28/2015   071/QR/01/02/15   Andy      YES       2205.49     0.00
2   2/16/2015   028/AA/01/02/15   Andy      NO        0.00        2205.49
4   7/14/2015   083/RF/01/07/15   Anna      YES       3822.60     0.00
7   7/14/2015   024/HU/01/07/15   Anna      NO        0.00        3822.60
12  8/10/2015   001/PR/01/08/15   Nicholas            11267.96    0.00
5   8/6/2015    030/AB/01/08/15   Anna      NO        0.00        11267.96
9   1/27/2015   007/ER/01/01/15   Jim       NO        5237.84     0.00
6   1/15/2015   020/TY/01/01/15   Barry               0.00        5237.84
13  10/31/2015  007/TX/09/10/15   Jim                 1780.84     0.00
8   1/31/2015   039/JK/01/01/15             YES       0.00        1780.84
1   4/30/2015   004/AB/01/04/15   Anna      YES       40239.66    0.00
10  4/29/2015   077/FX/01/04/15   Barry     NO        0.00        40239.66
11  1/3/2015    001/OX/10/01/15   Andy      NO        33074.03    0.00
15  1/7/2015    007/OM/02/01/15   Nicholas            8873.25     0.00
3   1/31/2015   021/DR/04/01/15   Jim       YES       167.60      0.00

老实说，我想不出正确的代码来做到这一点，这真的让我发疯。这是我失败的尝试之一，我尝试过类似的方法

Sub MatchingDebitAndCredit()
Dim i As Long, j As Long, Last_Row As Long
Last_Row = Cells(Rows.Count, "F").End(xlUp).Row

For i = 4 To Last_Row
For j = 4 To Last_Row
    If Cells(i, "F").Value = Cells(j, "G").Value And Cells(i, "G").Value = Cells(j, "F").Value Then
    Rows(i).EntireRow.Copy Destination:=Worksheets("Sheet2").Range("A" & Rows.Count).End(xlUp).Offset(1)
    Rows(j).EntireRow.Copy Destination:=Worksheets("Sheet2").Range("A" & Rows.Count).End(xlUp).Offset(1)
    Exit For
    End If
Next j
Next i
End Sub

我在 Sheet2 中复制了匹配的数据，因为我无法在同一张表中执行此操作，但它失败了，程序完成后 Sheet2 中没有返回任何内容。我打算使用数组和 Find 函数来做到这一点，因为数据集的大小非常大，但是如果使用工作表不能做到这一点，我怎么能做到呢？有人可以帮帮我吗？

Answer 1

如果我违反了这里的规则，对不起

我解决这个问题的方法是将我的数据值设置为一个数组，然后将借方金额设置为一个变量，然后循环返回数据集以找出是否有任何贷方与可变借方金额相匹配 - 我会组织然后，他们借方旁边的匹配项会经过并将数组组织得更干净一些，并将结果粘贴到工作表中。

我很想在更多数据上尝试一下，但是：

'constants declared for column numbers within array
Const lDEBITCOL As Long = 6
Const lCREDITCOL As Long = 7

Dim rA                                          'main array
Dim iMain&, stackRow&                           'module long variables
Dim debitAmt#                                   'module double variable

Sub raPairMain()

Dim j&

rA = ActiveSheet.UsedRange                      'setting activesheet into array

For iMain = 2 To UBound(rA)                     'imain loop through ra rows
    debitAmt = rA(iMain, lDEBITCOL)             'variable to check through credits in j loop
    'efficiency logical comparison for 0 values in debit amount
    'debit amount is 0 skip j loop
    If debitAmt Then

        For j = 2 To UBound(rA)                 'j loop through ra rows
            If debitAmt Then                    'necessary for matches on the last line of data
            'matching variable to credit amount in array
                If debitAmt = rA(j, lCREDITCOL) Then

                    'function to shift down rows within array
                    'first parameter(imain) is destination index
                    'second parameter is index to insert
                    'imain +1 to insert under current debit amount
                    shiftRaRowDown iMain + 1, j

                    Exit For
                End If                              'end of match for debit amount
            End If
        Next j                                  'increment j loop
    End If                                      'end of efficiency logical comparison
Next iMain                                      'increment imain loop

OrganizeArray                                   'procedure to stack array by matches

'setup array2 for dropping into worksheet to keep headings
'to preserve the table structure if present
ReDim rA2(UBound(rA) - 2, UBound(rA, 2) - 1)
Dim i&
For i = 2 To UBound(rA)
    For j = LBound(rA, 2) To UBound(rA, 2)
        rA2(i - 2, j - 1) = rA(i, j)
    Next j
Next i

'drop array2 into worksheet with offset
With ActiveSheet
    .Range(.Cells(2, 1), .Cells(UBound(rA), UBound(rA, 2))) = rA2
End With

End Sub

Sub OrganizeArray()
stackRow = 2                                    'initiate top row for stacking based on column headings
                                                'could also just constantly use row 2 and shift everything down
Dim i&, j&                                      'sub procedure long variables
Dim creditAmt#                                  'sub procedure double variable
    For i = 2 To UBound(rA)                     'initiate loop through ra rows
        debitAmt = rA(i, lDEBITCOL)             'set variable to find
        'efficiency check to bypass check if debit amount is null
        If debitAmt Then
            If i + 1 < UBound(rA) Then          'logical comparison for last array index
                'determine if next line is equal to variable debit amt
                If debitAmt = rA(i + 1, lCREDITCOL) Then
                    shiftRaRowDown stackRow, i  'insert in array position stack row as variable next top row
                    stackRow = stackRow + 1     'increment stack row based on new top row
                    'noted in primary procedure
                    shiftRaRowDown stackRow, i + 1
                    stackRow = stackRow + 1     'increment stack row for new top of array
                End If                          'end comparison for variable debit amount
            End If                              'end comparison for upper boundary of ra
        End If                                  'end comparison for null debit value
    Next i                                      'increment i loop
End Sub


Sub shiftRaRowDown(ByVal destinationIndex As Long, ByVal insertRow As Long)
    Dim i&, j&                                  'sub primary long variables for loop
    'for anytime the destination matches the insertion row exit sub procedure
    If destinationIndex = insertRow Then Exit Sub

    'if the destination row for debit was found after the credit amount
    'call the procedure again reversing the inputs and offsetting
    'debit / credit hierarchy
    If destinationIndex > insertRow Then
        shiftRaRowDown insertRow, destinationIndex - 1
        Select Case iMain
            Case Is < UBound(rA) - 1
                iMain = iMain + 1                      'increment main sub procedure i
            'reset debit amount to new main i value if it is within the array boundary
            Case Is <= UBound(rA)
                debitAmt = rA(iMain, lDEBITCOL)
            Case Else
                debitAmt = 0                        'necessary for matches on the last line of data
        End Select
        Exit Sub                                'exit recursive stack
    End If

    'get boundaries for a temporary storage array for row to insert
    ReDim tmparray(UBound(rA, 2))

    'function below will place data from array to move into temporary array
    tmparray = RowToInsert(insertRow)

    'initiate loop from the array copied temporary array back to the
    'row where it is being inserted
    For i = insertRow To destinationIndex Step -1

        'loop through columns to replace values
        For j = LBound(rA, 2) To UBound(rA, 2)
            rA(i, j) = rA(i - 1, j)             'values from previous row i-1 are set
        Next j
    Next i

    'loop through  temporary array to place copied temporary data
    For i = LBound(rA, 2) To UBound(rA, 2)

        'temporary array is single dimension
        rA(destinationIndex, i) = tmparray(i - 1)

    Next i
End Sub

Function RowToInsert(ByVal arrayIndex As Long) As Variant
    ReDim tmp(UBound(rA, 2) - 1)                'declare tempArray with boundaries offset for 0 address
    Dim i&                                      'sub procedure long iterator

    If arrayIndex > UBound(rA) Then
        RowToInsert = tmp
        Exit Function
    End If

    For i = LBound(tmp) To UBound(tmp)          'loop to store temporary values from array
        tmp(i) = rA(arrayIndex, i + 1)
    Next i
    RowToInsert = tmp                           'setting function = temporary array
End Function

好的 - 稍微改变了一点 - 我不确定我们现在是否需要在数组末尾移动的情况下，因为在主配对 j 循环中退出 for，但它按原样工作 - 无需花费更多的时间我会让你玩弄它。使用断点和你的本地窗口/debug.assert 来查看它在做什么。希望这会有所帮助

Answer 2

这似乎更容易使用辅助函数进行排序。例如

No  Date        Code            Name    Remarks Debit       Credit      match   sum
13  10/31/2015  007/TX/09/10/15 Jim             1,780.84    0.00        -1      1,780.84
8   1/31/2015   039/JK/01/01/15         YES     0.00        1,780.84    -1      1,780.84
14  2/28/2015   071/QR/01/02/15 Andy    YES     2,205.49    0.00        -1      2,205.49
2   2/16/2015   028/AA/01/02/15 Andy    NO      0.00        2,205.49    -1      2,205.49
4   7/14/2015   083/RF/01/07/15 Anna    YES     3,822.60    0.00        -1      3,822.60
7   7/14/2015   024/HU/01/07/15 Anna    NO      0.00        3,822.60    -1      3,822.60
9   1/27/2015   007/ER/01/01/15 Jim     NO      5,237.84    0.00        -1      5,237.84
6   1/15/2015   020/TY/01/01/15 Barry           0.00        5,237.84    -1      5,237.84
12  8/10/2015   001/PR/01/08/15 Nicholas        11,267.96   0.00        -1      11,267.96
5   8/6/2015    030/AB/01/08/15 Anna    NO      0.00        11,267.96   -1      11,267.96
1   4/30/2015   004/AB/01/04/15 Anna    YES     40,239.66   0.00        -1      40,239.66
10  4/29/2015   077/FX/01/04/15 Barry   NO      0.00        40,239.66   -1      40,239.66
3   1/31/2015   021/DR/04/01/15 Jim     YES     167.60      0.00        0       167.60
15  1/7/2015    007/OM/02/01/15 Nicholas        8,873.25    0.00        0       8,873.25
11  1/3/2015    001/OX/10/01/15 Andy    NO      33,074.03   0.00        0       33,074.03

我无法尝试代码，只是为了展示想法（假设数据在 Sheet2!A1:G16 中）

Sub MatchingDebitAndCredit()
    With Worksheets("Sheet2").Range("A2:I16")  ' exclude the headers row and include the columns for the helper functions

        .Columns("H").Formula = "= CountIf( $F:$F, $G2 ) * -( $G2 > $F2 ) + CountIf( $G:$G, $F2 ) * -( $F2 > $G2 ) " ' you can probably simplify this formula or combine it with the other one
        .Columns("I").Formula = "= $F2 + $G2 "

        .Sort key1:=.Range("H1"), key2:=.Range("I1"), key3:=.Range("G1")  ' sort by match, then by sum, and then by Credit (or adjust to your preference with Record Macro)

        .Columns("H:I").Clear ' optional to clear the helper functions
    End With
End Sub

Answer 3

改进

好的，我终于找到了自己的方法来解决这个问题。抱歉，如果需要的时间太长。我还要感谢Clyde 和Slai 他们给我的答案。我真的很感激。

我没有切割整行匹配数据，然后将其插入其对的行下方，这被认为是耗时的，而是根据匹配顺序，然后 delete（分配vbNullString）匹配的对，这样它们就不会通过遍历数组再次被处理。我还将内部循环的起点从i = 1 设置为j = i+1，因为要处理的下一个订单位于数据下方，因为在它上方找不到下一个匹配的候选。将所有数据标记为连续数字后，我根据列 ID 匹配（列 I）按升序对所有数据进行排序。为了提高代码性能，我将 F 和 G 列中的数据复制到一个数组中，我使用 .Value2 而不是 Excel 的默认设置，因为它只采用范围的值而没有其格式（借方和贷方采用会计数字格式）。这是我用来实现此任务的代码：

Sub Quick_Match()
Dim i As Long, j As Long, k As Long, Last_Row As Long
Dim DC, Row_Data, ID_Match
Last_Row = Cells(Rows.Count, "A").End(xlUp).Row
ReDim DC(1 To Last_Row - 1, 1 To 2)
ReDim Row_Data(1 To Last_Row - 1, 1 To 1)
ReDim ID_Match(1 To Last_Row - 1, 1 To 1)
DC = Range("A2:B" & Last_Row).Value2

For i = 1 To Last_Row - 2
    If DC(i, 1) <> vbNullString Then
            k = k + 1
            For j = i + 1 To Last_Row - 1
            If DC(j, 2) <> vbNullString Then
                If DC(i, 1) = DC(j, 2) And DC(i, 2) = DC(j, 1) Then
                    Row_Data(i, 1) = j + 1: ID_Match(i, 1) = k
                    Row_Data(j, 1) = i + 1: ID_Match(j, 1) = k
                    DC(i, 1) = vbNullString: DC(i, 2) = vbNullString
                    DC(j, 1) = vbNullString: DC(j, 2) = vbNullString
                    Exit For
                End If
            End If
            Next j
    End If

    If Row_Data(i, 1) = vbNullString Then
        Row_Data(i, 1) = "No Match": k = k - 1
    End If
Next i

Range("C2:C" & Last_Row) = Row_Data
Range("D2:D" & Last_Row) = ID_Match
Columns("A:D").Sort key1:=Range("D2"), order1:=xlAscending, Header:=xlYes
End Sub

在我的机器上处理大约 11,000 行时，它完成任务的时间平均不到 2.75 秒（比编辑前的版本快两倍，时间短得多）。详情请见the following post。