防止图像被阻止覆盖，因为它是作为背景动态加载的

Question

编辑：另见我关于这个程序的旧帖子以获取背景信息C# - Making a BackgroundImage update in real time while editing it in other programs

我创建了一个图像查看器，它将所选图像显示为“表单”的背景。

在我关闭程序之前，我加载的所有图像都不会被其他应用程序覆盖，例如 Photoshop 或 GIMP 等图像处理应用程序。

我的代码很简单：

public partial class Form1:Form {
    private string FileName;

    public Form1() {
        InitializeComponent();

        FileName = "";
        openFileDialog1.Filter = "PNG Files (*.png)|*.png|JPG Files (*.jpg)|*.jpg";
    }

    private void button1_Click( object sender, EventArgs e ) {
        if(openFileDialog1.ShowDialog() == DialogResult.OK) {
            button2.Enabled = true;
            FileName = openFileDialog1.FileName;
            setImage();
        }
    }

    private void button2_Click( object sender, EventArgs e ) {
        setImage();
    }

    private void setImage() {
        Stream str=new FileStream( FileName, FileMode.Open, FileAccess.Read, FileShare.Read);
        Bitmap tempImg= new Bitmap( Bitmap.FromStream(str) );
        str.Close();
        using( tempImg = new Bitmap(FileName) ) {
            Rectangle rect = new Rectangle(0, 0, tempImg.Width, tempImg.Height);
            PixelFormat format = tempImg.PixelFormat;

            this.BackgroundImage = new Bitmap(FileName).Clone(rect, format);
        }
        openFileDialog1.FileName = "";
    }
}

我该如何解决这个问题？

更新：

此代码对我不起作用。

    private void setImage() {
        // using (FileStream stream = new FileStream("MyImage.png", FileMode.Open, FileAccess.Read))
        //var image = Image.FromStream(stream); 
        using( new FileStream( FileName, FileMode.Open, FileAccess.Read, FileShare.Read) ) {
            Stream str=new FileStream( FileName, FileMode.Open, FileAccess.Read, FileShare.Read);
            Bitmap tempImg= new Bitmap( Bitmap.FromStream(str) );
            str.Close();
            tempImg = new Bitmap(FileName);
            Rectangle rect = new Rectangle(0, 0, tempImg.Width, tempImg.Height);
            PixelFormat format = tempImg.PixelFormat;

            this.BackgroundImage = new Bitmap(FileName).Clone(rect, format);
        }
        openFileDialog1.FileName = "";
    }

Answer 1

using (FileStream stream = new FileStream("MyImage.png", FileMode.Open, FileAccess.Read))
{
   var image = Image.FromStream(stream);

    // Do something with the image.
}

// The image will not be locked here.